Question

A box weighing 18 N requires a force of 6.0 N to drag it at a constant rate. What is the coefficient of sliding friction?



0.33

3.0

6.0

18

Answer 1

@Abhisar

Answer 2

Frictional force = \(\sf mg \mu\) = 6N

Find the value of \(\sf \mu\) by setting up an equation.

Answer 3

mg= weight

Answer 4

getting it?

Answer 5

6.0?

Answer 6

no,
18*\(\sf \mu\)=6,
can u find \(\sf \mu\) now?

Answer 7

nope

Answer 8

y?

\(\sf 18 \times \mu = 6\\ \mu = 6/18 =?\)

Answer 9

3.0?

Answer 10

you are dividing it wrong!

Answer 11

it's \(\frac {6}{18}~and~not~\frac{18}{6}\)

Answer 12

oh ok thnx