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Geometry 12 Online
OpenStudy (anonymous):

Find x in these 45 - 45 - 90 triangles.

OpenStudy (anonymous):

OpenStudy (anonymous):

@leonardo0430

OpenStudy (anonymous):

@sumanta ???

OpenStudy (anonymous):

-90

OpenStudy (anonymous):

it has to fill in the two blanks

OpenStudy (anonymous):

it would be like ?sqrt?

hartnn (hartnn):

-90 ? an angle isn't asked ... so, since we know its an 45-45-90 triangle, both of its legs will be =x By applying Pythagoras theorem \(\Large x^2+x^2 =8^2\) can you find x from here ?

OpenStudy (anonymous):

4?

OpenStudy (anonymous):

no wait

hartnn (hartnn):

not just 4 you need to first find x^2 and take the square root :) waiting...

OpenStudy (anonymous):

2x^2 = 64 right??

hartnn (hartnn):

yes

OpenStudy (anonymous):

so its 4 sqrt 2

OpenStudy (anonymous):

yes

hartnn (hartnn):

yes, 4 sqrt 2 is correct ! good!

OpenStudy (anonymous):

wooh! i have a few more??

hartnn (hartnn):

sure, ask!

OpenStudy (anonymous):

hartnn (hartnn):

you know in a 30-60-90 triangle what is side opposite to 60 degree in terms of hypotenuse?

OpenStudy (anonymous):

um lol. guessing like 30?

hartnn (hartnn):

close! :P side opposite to 60 degree = \(\sqrt 3 /2 \times \) hypotenuse :)

hartnn (hartnn):

so, in our diagram, we have side opposite to 60 degree as \(\huge 7\) so hypotenuse = y = \(\Large 7\times \sqrt 3/2\)

hartnn (hartnn):

and x is just the side opposite to 30 degrees, so it'll be half of the hypotenuse y x = y/2 = \(\Large 7\sqrt 3/4\)

hartnn (hartnn):

you need to remember these 2 things : `In a 30-60-90 Triangle, ` `Side opposite to 60 degree angle = sqrt 3/2 times the Hypotenuse` `Side opposite to 30 degree angle = 1/2 times the hypotenuse`

OpenStudy (anonymous):

ok lol so wait how will that fit into the choices they give?

hartnn (hartnn):

|dw:1421156048716:dw|

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