Question

Solve the system algebraically:
32x^2 + 9y^2 = 324
3y^2 - x^2 = 3

Answer 1

32x^2+9y^2=324
3y^2-x^2=3
this appears to be 2 equations ... Solve for the intersections?
3(3y^2-x^2=3 ) --- 9y^2 = 3x^2 +9 << sub into other equation
32x^2 + 3x^2 + 9 =324
35x^2 = 315
x^2 = 9 --- x = +/- 3
3y^2-x^2=3
for x = 3 --- 3y^2 = 12 --- y = +/-2
for x = -3 --- 3y^2 = 12 --- y = +/-2

(3,2), (3,-2), (-3,2), (-3,-2) << answers

Answer 2

(3,2), (3,-2), (-3,2), (-3,-2)

Answer 3

@blake57roger dont copy off the internet that's playgerisem

Answer 4

just the anwsers are the way you do it isnt

Answer 5

medal lol

Answer 6

dont copy other people