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Mathematics 19 Online
OpenStudy (anonymous):

An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t2 + 64t + 80?

OpenStudy (anonymous):

144 feet 123 feet 167 feet 172 feet

OpenStudy (anonymous):

@StudyGurl14

OpenStudy (anonymous):

@freckles

OpenStudy (anonymous):

i just really need help on how to set up the equation… i can do the rest.

OpenStudy (studygurl14):

Graph the parabola. Find it's maximum point.

OpenStudy (studygurl14):

its*

OpenStudy (anonymous):

but how do u do that… this is a random word problem they just threw in… I'm not used to them @StudyGurl14

OpenStudy (studygurl14):

You actually don't need to graph. Strike that. You can find the maximum point (vertex) without graphing. Look here: http://www.uiowa.edu/~examserv/mathmatters/tutorial_quiz/geometry/findingvertexofparabola.html

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