Question

what are the nature of the roots of the equation?

Answer 1

3x^2-5x=2

Answer 2

how much real roots, irrational roots, etc. are there?

Answer 3

Do you know how to find the discriminant of this equation?

Answer 4

yes . the discriminant is 1

Answer 5

Well, not quite! You have to first bring everything on one side.

Answer 6

what do you mean by bringing everything to one side?

Answer 7

Writing it in a form \(ax^2 + bx + c = 0\).

Answer 8

its 3x^2-5x-2=0

Answer 9

yup, find the discriminant now.

Answer 10

the discriminant is 1

Answer 11

Show your work.

Answer 12

y=3x^2-5x+2
discriminant = b^2-4(a)(c)
=(-5)^2-4(3)(2)=1

Answer 13

Recheck. Have you got all of your coefficients right?

Answer 14

yes . im pretty sure im correct .

Answer 15

a = 3, b = -5 and c = 2?

Answer 16

yes

Answer 17

3x^2 - 5x = 2.

3x^2 - 5x - 2 = 0.

Answer 18

yes.

Answer 19

a = 3, b = -5, c = -2.

Answer 20

wouldnt C=2

Answer 21

nvm . the discriminant is 49

Answer 22

i see what your talking about now . a = 3, b = -5, c = -2.
discriminant = b^2-4(a)(c)
= (-5)^2-4(3)(-2)=49