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Mathematics 10 Online
OpenStudy (anonymous):

What is the length of AC

OpenStudy (anonymous):

OpenStudy (anonymous):

ok let me type the equation

OpenStudy (anonymous):

use pythagoras theorem ac^2=ab^2+bc^2

OpenStudy (anonymous):

so its 20^2+15^2

OpenStudy (anonymous):

\[A ^{2}\times B ^{2}= c ^{2}\]

OpenStudy (anonymous):

so 15^2*20^2=C^2

OpenStudy (anonymous):

I got 625m

OpenStudy (anonymous):

i ment plus up there what an idiot am i 225+400=c

OpenStudy (anonymous):

Okay same with this one then? what is the length of AB

OpenStudy (anonymous):

ok then \[\sqrt{625}\]

syed98 (syedmohammed98):

Simply use the Pythagoras theorem i:e hyp^2 = base^2 + height^2 so hyp = AC BASE = 15 HEIGHT = 20 (HYP)^2 = 15^2 + 20^2 = 625

syed98 (syedmohammed98):

i hope u get it :)

OpenStudy (anonymous):

I already answered the first one. I need help with the second one.

OpenStudy (anonymous):

thank you @SyedMohammed98 & @skate-4-life270 and also @danish071996.

syed98 (syedmohammed98):

now when u get 625 simply take the square root of it i:e 25 thats the answer

OpenStudy (anonymous):

@SyedMohammed98 can you help me with the second one?

syed98 (syedmohammed98):

use the same formula which i have mentioned above .....(hyp)^2 = base^2 + height^2 (30)^2 = (base)^2 + (24)^2 (30)^2 - (24)^2 = base^2 900 - 576 = base^2 324 = base^2 square root of 324 18 = base base = AB which is 18m

syed98 (syedmohammed98):

I hope u get it :)

OpenStudy (anonymous):

thank you!

syed98 (syedmohammed98):

Your welcome.

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