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Mathematics 13 Online
OpenStudy (anonymous):

The length of a rectangle is 5 times the width. What is the perimeter of the rectangle if the width is 12 inches? A. 72 inches B. 120 inches C. 144 inches D. 240 inches @misty1212

OpenStudy (nincompoop):

The length of a rectangle is 5 times the width. What is the perimeter of the rectangle if the width is 12 inches? first, write down the formula for the perimeter of a rectangle \(\sf \large P_{rectangle} = (2\times length) + (2 \times width) \rightarrow P = 2L + 2W \) then it says that the length is 5 times the width, that is \(\sf \large L = 5W \) and if the width is 12 inches it will be \(\sf \large P = 2(5\times 12) + 2(12) \)

OpenStudy (anonymous):

@Pawtpie

OpenStudy (anonymous):

I don't understand

OpenStudy (anonymous):

So we need the perimeter, the distance around the rectangle.

OpenStudy (anonymous):

A rectangle of course has length and width:|dw:1421197101129:dw|

OpenStudy (anonymous):

The problem also says that the length of the rectangle is 5 times the width, so: \[l = 5w\]

OpenStudy (anonymous):

It also says that the width is 12 inches \[w = 12\]

OpenStudy (anonymous):

l=60

OpenStudy (anonymous):

Perfect :), and the width is 12, so you get: |dw:1421197278238:dw| So you can solve with the equation: \[2(60) + 2(12)\]

OpenStudy (anonymous):

|dw:1421197704513:dw|

OpenStudy (anonymous):

60*2+12*2 120+24 184

OpenStudy (anonymous):

Are you sure that 120 + 24 is 184? :)

OpenStudy (anonymous):

no sorry it is 144:}

OpenStudy (anonymous):

so it is c

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