A Labrador leaps over a hurdle. The function f(t) represents the height of the Labrador above the ground, in inches, at t seconds: \[f(t) = -16t^2 + 26t\] A foxhound jumps over the same hurdle. The table shows the height of the foxhound above the ground g(t), in inches, at t seconds: Time (t) g(t) 0 0 0.4 5.44 0.6 6.24 0.7 6.16 0.8 5.76 1.0 4 1.2 0 Compare and interpret the maximum of f(t) and g(t).
this is music, dude. anyhow do you see the maximum of g()?
g(t)*
Go to math
rofl what is happening to this site aaaa http://puu.sh/eu7CR.png correct. now to find the max of f(t), we look at the vertex, I believe
I found the max of f(t), its 13/16
26/32 or 13/16 lemme just wolfram it
Which is 0.8125
26/32 = 13/16
we can plug that in to find the time wolfram says it's at (0.8125, 10.5625)
Two maximums?
no this is the labradors maximum
Oh, lol, sorry, blonde moment
0.1825 is 13/16 don't worry :p
*0.8125
omg
:(
Was kidding cx
anyhow, I guess interpreting this = the Labrador max is at 0.8125 // 10.blah bloah the other thing is at 0.6 // 6.24' that means the labrador reaches its max later, and jumps 4 inches higher
So, the labrador jumped higher than the fox
I know rofl
Seem Legit, lmbo cx
yeah, and it also took longer to reach its maximum
Tysm tho c:
any time brah
I'm telling preetha huehuehue
I'll stop distracting you now lol
Lol cx ty
this is music
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