Question

radicals

Answer 1

@DanJS

Answer 2

k

Answer 3

This one is a little tricky, i think.
\[\frac{ 16^{-(1/4)} }{ 4^{-(1/2)} }\]

Answer 4

negative exponents, switch them to the other side of the fraction and change to positive exponent

Answer 5

\[\frac{ 1 }{ a^{-1} } = \frac{ a^1 }{ 1 }\]

Answer 6

oh yeah. we did this yesterday it think.

Answer 7

since both exponents are negative, just flip the fraction over and make them both positive

Answer 8

\[[\frac{ 16^{1/4} }{ 4^{1/2} }]^{-1} = \frac{ 1 }{ 16^{1/4}/ ~4^{1/2} }= \frac{ 4^{1/2} }{ 16^{1/4} }\]

Answer 9

Why doesn't this problem work if you just plug it into a calculator....I mean I did and got 1. does it change the answer??

Answer 10

it is 1

Answer 11

4 to the 1/2 is the same as square root of 4 = 2
16 to the 1/4 is the same as 4th root of 16 = 2 also

2/2 = 1

Answer 12

both the numerator and denominator come out to be 1/2 and divided becomes 1.

Answer 13

\[\frac{ \sqrt{4} }{ \sqrt[4]{16} }\]

Answer 14

okay, so how do you know if you can just plug it into your calculator or you actually have to work out the problem?

Answer 15

@DanJS

Answer 16

sorry back

Answer 17

for these types of probs, you can always just use a calculator, from the others, i think they want you to just simplify without using calculators to get decimal numbers...

Answer 18

simplify as much as you can, and leave the rest as a radical

Answer 19

got it. can you help me with one or two more?

Answer 20

\[[\frac{ 16^{1/4} }{ 4^{1/2} }]^{-1} = \frac{ 1 }{ 16^{1/4}/ ~4^{1/2} }= \frac{ 4^{1/2} }{ 16^{1/4} } = \frac{ 2 }{ 2 } = 1\]

Answer 21

you see 4 to the 1/2 power is the square root of 4 which is 2

Answer 22

16 to the 1/4th power is the 4th root of 16, 16=2*2*2*2 , 4th root of 16 is also 2

Answer 23

Yes, I see how you did that.

Answer 24

k, post more if ya have em

Answer 25

thanks