Question

Write an equation for a parabola with vertex (-6,2) that is congruent to y=1/2x^2 and opens down.

Answer 1

Never did this, but i'll give it a quick shot. give me 5 minutes

Answer 2

Got it!

Answer 3

your equation of 1/2x^2

start putting your vertex of (-6,2)

y coordinate vertex=1/2x^2+2

now plug the -6 for x to get

1/2(x+6)^2+2

simplify the binomial

1/2(x^2+12x+36)+2

halve everything to the parenthesis

1/2x^2+6x+18+2

add the 2

y=1/2x^2+6x+20

plug the vertex of (-6,2) back in, if this equation is right, y=x

2=1/2(-6)^2+6(-6)+20

2=2

Answer 4

Gotcha! So the equation is y=1/2x^2+6x+20?

Answer 5

yes. you can even graph it and it's clearly downwards with a vertex if -6,2

Answer 6

gotcha! Thanks a ton! Really cleared matters up!

Answer 7

I hope so. Honestly, I looked at a question with the answer very similar to this and followed the same instructions for your question.