not sure what there is to show
you need to have \(f\) be continuous, which is the same as saying
\[g(a)=h(a)\]
OpenStudy (loser66):
Yes, it is
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (misty1212):
i mean that is one part
you can drag it out
\[\lim_{x\to a^+}f(x)=g(a)\\
\lim_{x\to a ^-}f(x)=g(a)\] so if \(g(a)=h(a)\) then the limit exists and is that number
OpenStudy (misty1212):
i made a mistake on the second line it should be \(h(a)\)
OpenStudy (loser66):
Yes, how about the opposite direction?
OpenStudy (misty1212):
guess you are not finished though you also have to say the derivatives are the same too right?
OpenStudy (misty1212):
oh but you are given that they are, so there is not too much to say ...
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (loser66):
I think derivative part is for the opposite direction, right?