PLEASE HELP!! MEDAL!! SOLVE FOR X:
\[\sqrt[3]{4X+1}=5\]
undo the root
get the cube of each side so it undoes the root on the left-hand side and then try to solve for x
@TheEdwardsFamily I cant write 3 inside the square root
oh
what do you get the cube in each side?? @nincompoop
a) x=-31 b)x=6 c)x=31 d)no real solution
i think its d
did you know that your problem is the same as \( (4x+1)^{\frac{1}{3}}=5^\frac{1}{1}\) if you cube both sides, you are essentially \( (4x+1)^{\frac{1}{3} \times \frac{3}{1}}=5^{\frac{3}{1}}\)
@Nnesha
@sleepyjess show your skills
huh? why me? :(
yes @claim ??
try to pick up where I left off, @sleepyjess
i have no clue what is this
I ALREADY GAVE YOU THE CLUE!
okay so you have to take cube both side so you can cancel cube root on left side
do you not know how to multiply, add, subtract and divide? learn the laws of exponents!
Ok, so nin is basically saying that your problem is the left side to the power of 1/3 and the right side is just to the power of 1. Now cube both sides to get ride of 1/3 and make it 1.
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