Question

\[2^{\frac{5}{2}} - 2^{\frac{3}{2}}\]can anyone help solve this? like provide an example of the process? answer not needed, just need a start on this

the fractions are exponents btw

The correct answer given was \[2^{\frac{3}{2}}\]

\[\text{Solved, thank you very much!}\] @Abhisar

Answer 1

I will do it like this

\(\sf \huge 2^{\frac{5}{2}} = \frac{1}{2^5}\)

Answer 2

wut
that's possible

Answer 3

*Is very rusty in algebra.*

Answer 4

oops...one min

Answer 5

xD

Answer 6

I will do it like this

\(\sf \huge 2^{\frac{5}{2}} = \sqrt{2}^5\)

Answer 7

;) :)

Answer 8

o-o

Answer 9

Yes... The 5 is outside the radical?

Answer 10

\[\huge\sqrt[5]{2}\] ??

Answer 11

It is? I did it the way Abhi did it. ._.

Answer 12

That's outside the radical,, it's power of root 5

Answer 13

gotcho

Answer 14

I will do it like this

\(\sf \huge 2^{\frac{5}{2}} = (\sqrt{2})^5=?\)

Answer 15

Alright then o-o

Answer 16

\[(\sqrt{2})^{5}-(\sqrt{2})^{3} = (\sqrt{2})^{3}\left((\sqrt{2})^{2}-(\sqrt{2})^{0}\right)\]\[(\sqrt{2})^{3}\left(2-1\right) = (\sqrt{2})^{3}(1) = (\sqrt{2})^{3}\]\[\text{This simplifies to } 2^{\frac{3}{2}}\]\[\text{I have the correct answer. Thank you}\] @Abhisar

Answer 17

Welcome ^_^

Answer 18

^-^