Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and provide the leading term. -3x5 + 9x4 + 5x3 + 3
@Lakeekee_
nomallyi would factor the polynomial orr factor by grouping the polynomial but you cant factor this one so im not sure on the answer im sorry
@iGreen @KamiBug @amberxoxo @phi
thnx for trying doe @Lakeekee_
yw boo @Tazmaniadevil and @LichKing
@cupcakerain
All even degree polynomials \[x^2, x^4, x^6, \ldots\] are such that as you tend towards negative or positive infinity (i.e. as you go all the way to the left or all the way to the right), both ends either go up or down. Just think about the graph of a parabola x^2. All odd degree polynomials \[x^3, x^5, x^7, \ldots\] are such that one end goes up and the other goes down. For the graph of x^3, as you go to the left, you tend towards more negative y values (the graph goes down) and as you go to the right, you tend towards more positive y values (the graph goes up). The leading degree of your polynomial is 5 (odd), so that suggests that one end goes up and the other goes down. However, the leading coefficient is negative, suggesting that it is flipped over the x-axis. What do you think the behavior is like? If you're confused, you can always plot the polynomial.
ya this dude just kilt me brain no im even more confused sombody got the how to do this problem for dummies explanation plz lol
@wyattp17 @VortexAlliby
hhaha gimme a sec
nvm... no ducking idea sorry tazz
zammmitttt
@Directrix
Here's a plot of x^2 and x^3 to help you see
Notice how for x^2, both ends go up while for x^3, one end goes up while the other goes down.
@Directrix plz come and help i need to got to work and this people are confusing me i need your guidance oh great master
http://msenux.redwoods.edu/IntAlgText/chapter6/section1.pdf go to this website boo it will explain how to do it
@igreen help me master of math
ur getting ignored *taunts you* ur getting ignored ha hah ha ha ha ha *chants*
jkjk
There's a graph of it..
@Lakeekee_ your goin to let her tuant you boo like that shame jk jk jk lol
ok so how do i do this problem
Have you looked at the graph that @iGreen posted?
yes i did but it says to What is the end behavior of the graph? Describe the end behavior and provide the leading term. so how do i do this
I believe this graph is negative..therefore the leading term would be negative..
leading coefficient*
O_O ok i guess that makes since lol
The leading term has the highest power of x: So what is it? P{x) = -3x5 + 9x4 + 5x3 + 3
um im guessing x5
i ment 5 x lol
Five is correct.
So, this is the leading term: -3x5
ook
In the end, it does not matter what these terms do: + 9x4 + 5x3 + 3
They are along for the ride.
-3x^5 is the driver.
The question is about the end behavior of this: P(x) = -3x5 + 9x4 + 5x3 + 3
I find this very helpful: http://hotmath.com/hotmath_help/topics/end-behavior-of-a-function.html
That is the same as asking how -3x^5 behaves as x gets larger and larger (as x approaches infinity)
ok i understand that
Is 5 an odd or even number? @Tazmaniadevil
odd
Look at the lead term again: -3x^5 Negative 3 times x raised to the 5th power
ok so what am i looking for
x raised to the 5th power
Right, so it's Degree is Odd, and I said it's Leading Coefficient is negative..so looking at the link I sent you, look at the table and see which one is both 'Odd' and 'Negative', then look at the End Behavior..it will give you your answer.
Go ahead and finish @iGreen
@cupcakerain @Lakeekee_ has something to tell you lol
sure :) go ahead girl
ok thianks guys i think i got the rest
Okay, what did you come up with the End Behavior?
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thas all u wanna say to me?
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i mena dont be fighting in my math question fyall dont wanna get in troulbe now ya here
sorry i got graph is negative..therefore the leading coefficient would be negative.. becuase it has a negative ending int he eqaution
am i right @iGreen
Yes.. The link I gave you says that if the Leading Coefficient is Negative, and the Degree is Odd, the end behavior will be as P(x) approaches positive infinity, x will approach negative infinity. And as x approaches positive infinity, P(x) will approach negative infinity.
thnx again @iGreen you da best
No problem.
And GO BRONCOS! ;P
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^ ALWAYS AND FOREVRE BRONCOS RULE THE NFL YEEEE BOIIIII!!!!!!
AND THOSE THAT APEAL WHAT I SAY SHAL HAVE A LONG DEFEING FEATH
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