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Mathematics 14 Online
OpenStudy (anonymous):

Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and provide the leading term. -3x5 + 9x4 + 5x3 + 3

OpenStudy (anonymous):

@Lakeekee_

OpenStudy (anonymous):

nomallyi would factor the polynomial orr factor by grouping the polynomial but you cant factor this one so im not sure on the answer im sorry

OpenStudy (anonymous):

@iGreen @KamiBug @amberxoxo @phi

OpenStudy (anonymous):

thnx for trying doe @Lakeekee_

OpenStudy (anonymous):

yw boo @Tazmaniadevil and @LichKing

OpenStudy (anonymous):

@cupcakerain

OpenStudy (displayerror):

All even degree polynomials \[x^2, x^4, x^6, \ldots\] are such that as you tend towards negative or positive infinity (i.e. as you go all the way to the left or all the way to the right), both ends either go up or down. Just think about the graph of a parabola x^2. All odd degree polynomials \[x^3, x^5, x^7, \ldots\] are such that one end goes up and the other goes down. For the graph of x^3, as you go to the left, you tend towards more negative y values (the graph goes down) and as you go to the right, you tend towards more positive y values (the graph goes up). The leading degree of your polynomial is 5 (odd), so that suggests that one end goes up and the other goes down. However, the leading coefficient is negative, suggesting that it is flipped over the x-axis. What do you think the behavior is like? If you're confused, you can always plot the polynomial.

OpenStudy (anonymous):

ya this dude just kilt me brain no im even more confused sombody got the how to do this problem for dummies explanation plz lol

OpenStudy (anonymous):

@wyattp17 @VortexAlliby

OpenStudy (anonymous):

hhaha gimme a sec

OpenStudy (anonymous):

nvm... no ducking idea sorry tazz

OpenStudy (anonymous):

zammmitttt

OpenStudy (anonymous):

@Directrix

OpenStudy (displayerror):

Here's a plot of x^2 and x^3 to help you see

OpenStudy (displayerror):

Notice how for x^2, both ends go up while for x^3, one end goes up while the other goes down.

OpenStudy (anonymous):

@Directrix plz come and help i need to got to work and this people are confusing me i need your guidance oh great master

OpenStudy (anonymous):

http://msenux.redwoods.edu/IntAlgText/chapter6/section1.pdf go to this website boo it will explain how to do it

OpenStudy (anonymous):

@igreen help me master of math

OpenStudy (anonymous):

ur getting ignored *taunts you* ur getting ignored ha hah ha ha ha ha *chants*

OpenStudy (anonymous):

jkjk

OpenStudy (igreen):

https://www.desmos.com/calculator/rsotev49ri

OpenStudy (igreen):

There's a graph of it..

OpenStudy (anonymous):

@Lakeekee_ your goin to let her tuant you boo like that shame jk jk jk lol

OpenStudy (anonymous):

ok so how do i do this problem

OpenStudy (displayerror):

Have you looked at the graph that @iGreen posted?

OpenStudy (anonymous):

yes i did but it says to What is the end behavior of the graph? Describe the end behavior and provide the leading term. so how do i do this

OpenStudy (igreen):

I believe this graph is negative..therefore the leading term would be negative..

OpenStudy (igreen):

leading coefficient*

OpenStudy (anonymous):

O_O ok i guess that makes since lol

Directrix (directrix):

The leading term has the highest power of x: So what is it? P{x) = -3x5 + 9x4 + 5x3 + 3

OpenStudy (anonymous):

um im guessing x5

OpenStudy (anonymous):

i ment 5 x lol

Directrix (directrix):

Five is correct.

Directrix (directrix):

So, this is the leading term: -3x5

OpenStudy (anonymous):

ook

Directrix (directrix):

In the end, it does not matter what these terms do: + 9x4 + 5x3 + 3

Directrix (directrix):

They are along for the ride.

Directrix (directrix):

-3x^5 is the driver.

Directrix (directrix):

The question is about the end behavior of this: P(x) = -3x5 + 9x4 + 5x3 + 3

OpenStudy (igreen):

I find this very helpful: http://hotmath.com/hotmath_help/topics/end-behavior-of-a-function.html

Directrix (directrix):

That is the same as asking how -3x^5 behaves as x gets larger and larger (as x approaches infinity)

OpenStudy (anonymous):

ok i understand that

OpenStudy (igreen):

Is 5 an odd or even number? @Tazmaniadevil

OpenStudy (anonymous):

odd

Directrix (directrix):

Look at the lead term again: -3x^5 Negative 3 times x raised to the 5th power

OpenStudy (anonymous):

ok so what am i looking for

Directrix (directrix):

x raised to the 5th power

OpenStudy (igreen):

Right, so it's Degree is Odd, and I said it's Leading Coefficient is negative..so looking at the link I sent you, look at the table and see which one is both 'Odd' and 'Negative', then look at the End Behavior..it will give you your answer.

Directrix (directrix):

Go ahead and finish @iGreen

OpenStudy (anonymous):

@cupcakerain @Lakeekee_ has something to tell you lol

OpenStudy (anonymous):

sure :) go ahead girl

OpenStudy (anonymous):

ok thianks guys i think i got the rest

OpenStudy (igreen):

Okay, what did you come up with the End Behavior?

OpenStudy (anonymous):

dont sas my maan jkjkjkjk lol

OpenStudy (anonymous):

thas all u wanna say to me?

OpenStudy (anonymous):

cat fight do it do it do it

OpenStudy (anonymous):

i mena dont be fighting in my math question fyall dont wanna get in troulbe now ya here

OpenStudy (anonymous):

sorry i got graph is negative..therefore the leading coefficient would be negative.. becuase it has a negative ending int he eqaution

OpenStudy (anonymous):

am i right @iGreen

OpenStudy (igreen):

Yes.. The link I gave you says that if the Leading Coefficient is Negative, and the Degree is Odd, the end behavior will be as P(x) approaches positive infinity, x will approach negative infinity. And as x approaches positive infinity, P(x) will approach negative infinity.

OpenStudy (anonymous):

thnx again @iGreen you da best

OpenStudy (igreen):

No problem.

OpenStudy (igreen):

And GO BRONCOS! ;P

OpenStudy (anonymous):

^^yesh^^

OpenStudy (anonymous):

^ ALWAYS AND FOREVRE BRONCOS RULE THE NFL YEEEE BOIIIII!!!!!!

OpenStudy (anonymous):

AND THOSE THAT APEAL WHAT I SAY SHAL HAVE A LONG DEFEING FEATH

OpenStudy (anonymous):

i menat death lol

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