Question

graph f(theta) = sin(theta) where -2pi < theta < 2pi

Answer 1

do you know how sin(theta) looks like?

Answer 2

no @xapproachesinfinity

Answer 3

well then you can't draw this if you no idea at all
at least you should know some values for sin
make a table of values btw -2pi to 2pi
see if you can do it

Answer 4

here is what you need to know
sin is a periodic function with period 2pi
meaning it repeats every 2pi the same values
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it is an odd function meaning it is symmeterical with respect to the origin (0,0)

Answer 5

so if you can draw it from 0 to pi
you will be able to draw it from -2pi to 2pi

Answer 6

i mean 0 to 2pi

Answer 7

here is the graph
http://www.had2know.com/images/graph-sinx.png

Answer 8

so you never seen that graph before?

Answer 9

I have.

Answer 10

well that's what they are asking you to do

Answer 11

so they just want you to draw that graph?

Answer 12

to be able to know why that make sense
you need to see what happens in these intervals:
[0,pi/2] [pi/2,pi] [pi,2pi]
once you found out the rest in just make use of symmetry and the period

Answer 13

yes!

Answer 14

do this table