Question

Divide (x^3+2-5)÷(x-3)
Please explain this and how you would solve it

Answer 1

@mathmate

Answer 2

@Daniellelovee
Hey! Is this a long division issue, or factorization?
It looks like there will be remainders!

Answer 3

Is it
\(\dfrac{x^3+2x-5}{x-3}\), or
\(\dfrac{x^3+2x^2-5}{x-3}\)?

Answer 4

I don't think you can factor it

Answer 5

ok how did you get there

Answer 6

(x^3+2-5)÷(x-3)
this is the equation, the 2 does not have an x

Answer 7

I am not sure about the question.
The coefficient 2 does not have a power of x to go with it.
I am just checking what the question is like, so far.

Answer 8

thats what Im confused about because if the 2 had an x I would factor it and then divide normally but since it doesn't im just confused

Answer 9

and there is no lest common factor either

Answer 10

so that would be \(\dfrac{x^3+2-5}{x-3}=\dfrac{x^3-3}{x-3}\) then

Answer 11

That is why I thought something is missing.

Answer 12

Even if we put 2x or 2x^2, the numerator does not have rational factors.

Answer 13

so the answer is x once you divide right?

Answer 14

because the x-3 cancels out

Answer 15

\(\dfrac{x^3+2-5}{x-3}=\dfrac{x^3-3}{x-3}=x^2+3x+9~with~remainder~24\)

Answer 16

Not sure if that's what you need.
Can you double check the question, the +2-3 looks "fishy".

Answer 17

* +2-5

Answer 18

Well, if the numerator does not factorize, then the x-3 cannot cancel out. The best we can do is to divide and state the remainder.

Answer 19

lol nvm it was probably a typo since this was a practice question before the quiz

Answer 20

I just wanted to make sure I wasn't the only one that thought that this question was odd.

Answer 21

I think there must be a type, we don't usually write x^3+2-5! lol