Question

Math help plz asap win medal
Julie solved eachof the equations. To solve the first equation, she added first and then multiplied.To solve the second equation, she multiplied first then added. Why did Julie add and multiply in a different order each time? Explain your thinking.
1/8a-3/4=1/2
a-5/9=1/3

Answer 1

I's on my math book but it's called core focus i hate those can you help me?

Answer 2

Well try it yourself, you have the equation 1/8a-3/4=1/2 do the steps Julie did and see what you get and see if it's right or not, it's just simple algebra really :P

Answer 3

ok

Answer 4

so for the first equation it would be 1/8a+3/4=12 that's step on because she added

Answer 5

No, you want to isolate a, meaning get a by its self.
\[1/8a-3/4=12 \implies 1/8a-3/4\color{red}{+3/4}=12\color{red}{+3/4}\]

Answer 6

As your question doesn't specify what she is adding/ multiplying by so we will have to go with this :)

Answer 7

ok 3/4+3/4 is either take 3/4 away or add it up

Answer 8

but 12+3/4 would be 12 and 3/4?

Answer 9

You want to get `a` by itself, so to do that we use the opposite operation to move everything other than a to the right.

Answer 10

ok

Answer 11

12+3/4 = 51/4

Answer 12

\[1/8a=51/4\] so now we have this

Answer 13

ok so then 1/8a=51/4 right what we could do is 1/8 divided by 1/8 on both sides

Answer 14

Nope because we want to cancel out the 1/8 on the left, if we divide by 1/8 on the left side we would just get 1/64a

Answer 15

So why don't we multiply by 8 on both sides instead? :P

Answer 16

\[8 \times \frac{ 1 }{ 8 }a = \frac{ 51 }{ 4 } \times 8\]

Answer 17

so then next we multiply 51/4*8=102

Answer 18

Yes, so a = 102

Answer 19

ok thank you