Question

I'm sorry I know this is math but no one's helping me in that forum so please help if you can
Simplify
1. 5-3x+y+6
2. 2x+3(x-5)+9
3. -20-(-5)*(-5)[2squared]
the bracketed part "2squared" is supposed to be exactly what is says. But, there's no way to put an actual squared number.

Answer 1

For the first one all you have to do is 5+6.
Second one distribute 3 over (x-5) meaning multiply 3 by both x and -5, and collect like terms.
When you have exponents you can use this "hat" 2^2 that implies squared, you can also write 2^100 etc, but for that one just used PEDMAS/ BEDMAS what ever suits you.
Show us an attempt and we'll go from there, good luck.

Answer 2

thank you, batman.
so first is 11-3x+y
and second 5x-15+9? or would it be 5x-24? Is it correct to combine something inside the parenthesis to outside of it?
third... Do I really just use PEMDAS?

Answer 3

First one right
Second one 5x-15+9 =>5x-6 that's good
Yes ;)

Answer 4

Thank you so much!
But... How do I use pemdas if everything is in parenthesis? It's an odd problem to work with, I don't know where to start on it.

Answer 5

just work with everything thats in the parenthesis as PEMDAS States

Answer 6

I honestly have no idea what to do for it...

Answer 7

\[-20-(-5)(-5)*(2^2)\] so first 2^2 = 4
(-5)(-5) = 25, so (25)(4) = 100
-20-100 = ?

Answer 8

Then you mulyiply

Answer 9

Since they are both in brackets go in order with pedmas, you see exponents is right after parenthesis so go with that since it's the next operation :)

Answer 10

Ok @Sarcasmus i'll help you here if you help me in french?

Answer 11

Does that make sense?

Answer 12

Parenthesis Exponent Multiplication Division Addition Subtraction
you break down a problem in this order.