Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (ayyookyndall):

Complete the two column proof. Given: m

OpenStudy (ayyookyndall):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

going from m<RST + m<UVW = 180 to 5x + 7x = 180 what changed?

OpenStudy (ayyookyndall):

Substitute? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

yes, you substituted in m<RST = 5x and m<UVW = 7x they are given

jimthompson5910 (jim_thompson5910):

so that is essentially the reason they want

jimthompson5910 (jim_thompson5910):

from there 5x+7x turns into 12x you can say "addition" or "combine like terms" or something like that

OpenStudy (ayyookyndall):

So a. is given?

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

m<RST = 5x and m<UVW = 7x are given

jimthompson5910 (jim_thompson5910):

you already said the reason for a) starts with an s

OpenStudy (ayyookyndall):

So a. is substitution

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (ayyookyndall):

b. Addition Property of Equality?

jimthompson5910 (jim_thompson5910):

nope, that property is the idea that if a = b, then a+c = b+c

jimthompson5910 (jim_thompson5910):

example: 2x-3 = 5 2x-3+3 = 5+3 ... used the property here 2x = 6

jimthompson5910 (jim_thompson5910):

basically adding the same number to both sides

OpenStudy (ayyookyndall):

b. Combine like terms

jimthompson5910 (jim_thompson5910):

yeah that sounds good

OpenStudy (ayyookyndall):

okay what about c?

jimthompson5910 (jim_thompson5910):

what's changing there

jimthompson5910 (jim_thompson5910):

going from 12x = 180 to x = 15

OpenStudy (ayyookyndall):

c. Division

jimthompson5910 (jim_thompson5910):

there's more to it, but division is part of it

OpenStudy (ayyookyndall):

Division Property of Equality?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

if a = b, then a/c = b/c assuming c is nonzero

OpenStudy (ayyookyndall):

So thats c.?

jimthompson5910 (jim_thompson5910):

I'm assuming you're in geometry class. This proof is simply a rigorous way to solve a problem you'd do back in algebra 1 or 2.

jimthompson5910 (jim_thompson5910):

yeah

OpenStudy (ayyookyndall):

Can you help me with more?

jimthompson5910 (jim_thompson5910):

sure, a few more

OpenStudy (ayyookyndall):

Triangle TIC is an isosceles triangle with vertex angle I. Find the measures of the base angles of Triangle TIC if m< I = 100. a. 80 b. 50 c. 60 d. 40 Is it A?

jimthompson5910 (jim_thompson5910):

|dw:1421292178255:dw|

jimthompson5910 (jim_thompson5910):

|dw:1421292204838:dw|

jimthompson5910 (jim_thompson5910):

the base angles of any isosceles triangle are always congruent they are both x for now

OpenStudy (ayyookyndall):

Oh its 40...

jimthompson5910 (jim_thompson5910):

all 3 angles of ANY triangle add to 180 degrees x+x+100 = 180

jimthompson5910 (jim_thompson5910):

yeah if you solved x+x+100 = 180, you'd get x = 40

jimthompson5910 (jim_thompson5910):

so if in doubt, draw a picture

OpenStudy (ayyookyndall):

Find the length of a diagonal of a rectangle ABCD with vertices A (-3, 1), B (-1, 3), C(3, -1), and D(1, -3) a. 5.7 b. 6.3 c. 3.2 d. 4.5

jimthompson5910 (jim_thompson5910):

the diagonals are the segments AC and BD

jimthompson5910 (jim_thompson5910):

to find the length of AC, you find the distance from A to C so you use the distance formula \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]

jimthompson5910 (jim_thompson5910):

what do you get?

OpenStudy (ayyookyndall):

I got D @jim_thompson5910 Sorry I went to go do something

jimthompson5910 (jim_thompson5910):

its ok, I had to step away also

jimthompson5910 (jim_thompson5910):

what did you get before you took the square root?

OpenStudy (ayyookyndall):

20.25

jimthompson5910 (jim_thompson5910):

that's incorrect

jimthompson5910 (jim_thompson5910):

Find the distance from A to C to get: \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] \[\Large d = \sqrt{\left(-3-3\right)^2+\left(1-(-1)\right)^2}\] \[\Large d = \sqrt{\left(-6\right)^2+\left(2\right)^2}\] \[\Large d = \sqrt{36+4}\] \[\Large d = \sqrt{40}\] \[\Large d \approx 6.32\]

OpenStudy (ayyookyndall):

Oh. I feel so dumb... ugh

OpenStudy (ayyookyndall):

I wanted you to clarify some stuff with me is that okay?

jimthompson5910 (jim_thompson5910):

which part did you make a mistake at?

OpenStudy (ayyookyndall):

The first.. I didnt type it in right

jimthompson5910 (jim_thompson5910):

so you see how I got A = (x1,y1) = (-3, 1) C = (x2,y2) = (3, -1) or no?

OpenStudy (ayyookyndall):

Yes. thank you

OpenStudy (ayyookyndall):

I need help with some clarify some other questions too... Someone was helping me and got me all confused

jimthompson5910 (jim_thompson5910):

whats that

OpenStudy (ayyookyndall):

State the property that justifies the statement: If 3x = 6, then x = 2 a. Subtraction Property of Equality b. Addition Property of Equality c. Division Property of Equality d. Multiplication Property of Equality Given that AD and BC are parallel, find the value of x. a. 15 b. 5 c. 12.5 d. 17.5

OpenStudy (ayyookyndall):

The first one they said is C... but how is that? Its multiplying...

OpenStudy (ayyookyndall):

The second one they said is a ... I have no idea how they got that

jimthompson5910 (jim_thompson5910):

If 3x = 6, then x = 2 so you do what to both sides?

OpenStudy (ayyookyndall):

Divide...

jimthompson5910 (jim_thompson5910):

yes you divide both sides by _____

OpenStudy (ayyookyndall):

2...

OpenStudy (ayyookyndall):

Ohhh okay. Gosh I feel mean.. haha

jimthompson5910 (jim_thompson5910):

the ultimate goal is to go from 3x to just x

jimthompson5910 (jim_thompson5910):

|dw:1421294418302:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!