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OpenStudy (ayyookyndall):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
going from
m<RST + m<UVW = 180
to
5x + 7x = 180
what changed?
OpenStudy (ayyookyndall):
Substitute?
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
yes, you substituted in m<RST = 5x and m<UVW = 7x
they are given
jimthompson5910 (jim_thompson5910):
so that is essentially the reason they want
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jimthompson5910 (jim_thompson5910):
from there 5x+7x turns into 12x
you can say "addition" or "combine like terms" or something like that
OpenStudy (ayyookyndall):
So a. is given?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
m<RST = 5x and m<UVW = 7x are given
jimthompson5910 (jim_thompson5910):
you already said the reason for a)
starts with an s
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OpenStudy (ayyookyndall):
So a. is substitution
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (ayyookyndall):
b. Addition Property of Equality?
jimthompson5910 (jim_thompson5910):
nope, that property is the idea that if a = b, then a+c = b+c
jimthompson5910 (jim_thompson5910):
example:
2x-3 = 5
2x-3+3 = 5+3 ... used the property here
2x = 6
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jimthompson5910 (jim_thompson5910):
basically adding the same number to both sides
OpenStudy (ayyookyndall):
b. Combine like terms
jimthompson5910 (jim_thompson5910):
yeah that sounds good
OpenStudy (ayyookyndall):
okay what about c?
jimthompson5910 (jim_thompson5910):
what's changing there
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jimthompson5910 (jim_thompson5910):
going from
12x = 180
to
x = 15
OpenStudy (ayyookyndall):
c. Division
jimthompson5910 (jim_thompson5910):
there's more to it, but division is part of it
OpenStudy (ayyookyndall):
Division Property of Equality?
jimthompson5910 (jim_thompson5910):
yes
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jimthompson5910 (jim_thompson5910):
if a = b, then a/c = b/c assuming c is nonzero
OpenStudy (ayyookyndall):
So thats c.?
jimthompson5910 (jim_thompson5910):
I'm assuming you're in geometry class. This proof is simply a rigorous way to solve a problem you'd do back in algebra 1 or 2.
jimthompson5910 (jim_thompson5910):
yeah
OpenStudy (ayyookyndall):
Can you help me with more?
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jimthompson5910 (jim_thompson5910):
sure, a few more
OpenStudy (ayyookyndall):
Triangle TIC is an isosceles triangle with vertex angle I. Find the measures of the base angles of Triangle TIC if m< I = 100.
a. 80
b. 50
c. 60
d. 40
Is it A?
jimthompson5910 (jim_thompson5910):
|dw:1421292178255:dw|
jimthompson5910 (jim_thompson5910):
|dw:1421292204838:dw|
jimthompson5910 (jim_thompson5910):
the base angles of any isosceles triangle are always congruent
they are both x for now
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OpenStudy (ayyookyndall):
Oh its 40...
jimthompson5910 (jim_thompson5910):
all 3 angles of ANY triangle add to 180 degrees
x+x+100 = 180
jimthompson5910 (jim_thompson5910):
yeah if you solved x+x+100 = 180, you'd get x = 40
jimthompson5910 (jim_thompson5910):
so if in doubt, draw a picture
OpenStudy (ayyookyndall):
Find the length of a diagonal of a rectangle ABCD with vertices A (-3, 1), B (-1, 3), C(3, -1), and D(1, -3)
a. 5.7
b. 6.3
c. 3.2
d. 4.5
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jimthompson5910 (jim_thompson5910):
the diagonals are the segments AC and BD
jimthompson5910 (jim_thompson5910):
to find the length of AC, you find the distance from A to C
so you use the distance formula
\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]
jimthompson5910 (jim_thompson5910):
what do you get?
OpenStudy (ayyookyndall):
I got D @jim_thompson5910
Sorry I went to go do something
jimthompson5910 (jim_thompson5910):
its ok, I had to step away also
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jimthompson5910 (jim_thompson5910):
what did you get before you took the square root?
OpenStudy (ayyookyndall):
20.25
jimthompson5910 (jim_thompson5910):
that's incorrect
jimthompson5910 (jim_thompson5910):
Find the distance from A to C to get:
\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]
\[\Large d = \sqrt{\left(-3-3\right)^2+\left(1-(-1)\right)^2}\]
\[\Large d = \sqrt{\left(-6\right)^2+\left(2\right)^2}\]
\[\Large d = \sqrt{36+4}\]
\[\Large d = \sqrt{40}\]
\[\Large d \approx 6.32\]
OpenStudy (ayyookyndall):
Oh. I feel so dumb... ugh
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OpenStudy (ayyookyndall):
I wanted you to clarify some stuff with me is that okay?
jimthompson5910 (jim_thompson5910):
which part did you make a mistake at?
OpenStudy (ayyookyndall):
The first.. I didnt type it in right
jimthompson5910 (jim_thompson5910):
so you see how I got
A = (x1,y1) = (-3, 1)
C = (x2,y2) = (3, -1)
or no?
OpenStudy (ayyookyndall):
Yes. thank you
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OpenStudy (ayyookyndall):
I need help with some clarify some other questions too...
Someone was helping me and got me all confused
jimthompson5910 (jim_thompson5910):
whats that
OpenStudy (ayyookyndall):
State the property that justifies the statement:
If 3x = 6, then x = 2
a. Subtraction Property of Equality
b. Addition Property of Equality
c. Division Property of Equality
d. Multiplication Property of Equality
Given that AD and BC are parallel, find the value of x.
a. 15
b. 5
c. 12.5
d. 17.5
OpenStudy (ayyookyndall):
The first one they said is C... but how is that? Its multiplying...
OpenStudy (ayyookyndall):
The second one they said is a ... I have no idea how they got that
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jimthompson5910 (jim_thompson5910):
If 3x = 6, then x = 2
so you do what to both sides?
OpenStudy (ayyookyndall):
Divide...
jimthompson5910 (jim_thompson5910):
yes you divide both sides by _____
OpenStudy (ayyookyndall):
2...
OpenStudy (ayyookyndall):
Ohhh okay. Gosh I feel mean.. haha
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