Question

Solve the system, using substitution.
3a - b = 11 and 2a + 3b = 0
A. (3, 2)
B. (3, -2)
C. (-3, 2)
D. (-3, -2)
E. no solution

Answer 1

need help with finding the right answer please

Answer 2

Assuming (a,b) .. sub in the values for the a and b variables. The results must be true for both equations.

Answer 3

So in substitution we need to define one of the variables ( a or b) and substitute it in the other equation

Answer 4

The the first equation 3a-b=11 and change to show b = ????

Answer 5

Plug them in and you'll get the answer o:

Answer 6

Substitute the multiple answer choices to see if the equations are true.

Answer 7

Oh feh xD Did not see the second one~

Answer 8

So do the first one by plugging (3,2) in both of the equations to see if they are true and if they are not true then move on to the next equation.

Answer 9

If I am allowed to..I will explain the first option and you can go from there

Answer 10

I'll start off with the first equation, if you don't know how to do it.

2( )-( )=11 2( )+3( )=0

Plug in (3,2) in for (a,b) so assume that a=3 and b=2

2(3)-(2)=11 2(3)+3(2)=0
6-2=11 6+6=0
4=11 12=0
No No


The first set of given coordinates don't work so do the next set of coordinates.

Answer 11

to use substitution
from one equation write the equivalent expression for one of the variables
use this expression in the other equation instead of writing the letter of the variable
you know have one equation with one unknown variable
solve for this variable then substitute this value in the expression to calculate the value of the other variable.

Answer 12

for this problem
from equation 1. b = 3a - 11
use this in equation 2
2a + 3(3a - 11) = 0
11a = 33 so a = 3
b = 3(3) - 11 = 9-11= -2
(3, -2)