Mathematics
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OpenStudy (anonymous):
What is a function whose domain is [2, infinity)?
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
@Zale101
OpenStudy (anonymous):
@triciaal
OpenStudy (xapproachesinfinity):
well many functions can have a domain of [2, infinity)
try to post your question accurately
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OpenStudy (anonymous):
it doesn't matter which one, I just need any one.
OpenStudy (triciaal):
f(x) : x >/= 2
OpenStudy (anonymous):
what is x >/ = 2??? Doesn't make sense...
OpenStudy (xapproachesinfinity):
hmm... not sure how that will help you but here
\(\large f(x)=\sqrt{x-2}\) domain is \(\large [2, \infty)\)
OpenStudy (triciaal):
greater than or equal to
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OpenStudy (triciaal):
lot of sense if you read the symbols right?
OpenStudy (xapproachesinfinity):
that's an example of a function that has that domain...
OpenStudy (xapproachesinfinity):
oh @triciaal has interpreted the meaning
if that's what you were looking for?
OpenStudy (anonymous):
@xapproachesinfinity That does not have (2, infinity) as the domain
OpenStudy (xapproachesinfinity):
hmm why not?
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OpenStudy (anonymous):
Idk, I just checked it and it said that the domain was all real non-negative numbers.....nvm I think it's right