According to the fundamental theorem of algebra, how many zeros does the polynomial below have?
f(x)=x^3+2x^2-6x-9

Question

According to the fundamental theorem of algebra, how many zeros does the polynomial below have? 
f(x)=x^3+2x^2-6x-9

ajspeller · Answer

At most the roots will be equal to the degree

ajspeller · Answer

Let me clarify zeros and roots are the same thing.  At most the number of roots/zeros will be the same as the degree of the polynomial.

anonymous · Answer

so if the degree is 3 then it has 3 zeros?

ajspeller · Answer

A most 3, but it could be 2, 1, or 0.

anonymous · Answer

oh gosh. that made this more complicated:(

directrix · Answer

The Fundamental Theorem of Algebra (FTA) states Every polynomial equation of degree n with complex coefficients has n roots in the complex numbers. http://www-history.mcs.st-and.ac.uk/HistTopics/Fund_theorem_of_algebra.html

ajspeller · Answer

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