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\[\frac{ (3+i)(4+2i) }{ (3-3i) }\]
I don't know how to do imaginary numbers with fractions...
k
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Ah! foil! I forgot.
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sec
yeah distribute out the numerator
remember i^2=-1
\[\frac{ (3+i)(4+2i) }{ (3-3i) } = \frac{ 12+10i+2i^2 }{ 3-3i }\]
and then: \[\frac{ 10+10i }{ 3-3i }\]
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yeah, then factor out 10 and 3
how do I do that exactly?
\[\frac{ 10 }{ 3 }*\frac{ 1+i }{ 1-i }\]
now multiply by the conjugate (1+i)/(1+i)
oh \[\frac{ 10i }{ 3 }\]
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yep
you are an angel sent from heaven to help me with my final! haha! You are wonderful!! :D
oh, i thought you took that... good luck!
they pushed it to Thursday. haha
oh nice, you will do fine
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