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Please help with this problem: http://snag.gy/OrREw.jpg
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take the first derivative of that function, and find out where it is zero. The slope of a tangent to the graph will be horizontal, zero. that will be the vertex of the parabola and the maximum revenue for a given price p
11,233.33?
R ' (p) = -30p + 200 find p, so that R '(p) = 0
that will be the price that will maximize the revenue. the point on the curve (p , R(p))
Oh, okay !^^ Thank you @DanJS
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i am just curious where did you get 11233.33
as the answer. since p=20/3
11233.33 is off the graph
(20/3 , 10667)
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20/3 goes in for p in the equation, I believe
But i'm never sure. I just go with yours. ^^
R(20/3) = \[R(\frac{ 20 }{ 3 })=-15(\frac{ 20 }{ 3 })^2+200*\frac{ 20 }{ 3 }+10000\]
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