Please help with this problem: http://snag.gy/OrREw.jpg

Question

danjs · Answer

take the first derivative of that function, and find out where it is zero. The slope of a tangent to the graph will be horizontal, zero. that will be the vertex of the parabola and the maximum revenue for a given price p

anonymous · Answer

11,233.33?

danjs · Answer

R ' (p) = -30p + 200

find p, so that R '(p) = 0

danjs · Answer

that will be the price that will maximize the revenue. the point on the curve (p , R(p))

anonymous · Answer

Oh, okay !^^ Thank you @DanJS

danjs · Answer

i am just curious where did you get 11233.33

anonymous · Answer

as the answer. since p=20/3

danjs · Answer

attachment

danjs · Answer

11233.33 is off the graph

danjs · Answer

(20/3 , 10667)

anonymous · Answer

20/3 goes in for p in the equation, I believe

anonymous · Answer

But i'm never sure. I just go with yours. ^^

danjs · Answer

R(20/3) = $$R(\frac{ 20 }{ 3 })=-15(\frac{ 20 }{ 3 })^2+200*\frac{ 20 }{ 3 }+10000$$