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Mathematics 19 Online
OpenStudy (anonymous):

Please help with this problem: http://snag.gy/OrREw.jpg

OpenStudy (danjs):

take the first derivative of that function, and find out where it is zero. The slope of a tangent to the graph will be horizontal, zero. that will be the vertex of the parabola and the maximum revenue for a given price p

OpenStudy (anonymous):

11,233.33?

OpenStudy (danjs):

R ' (p) = -30p + 200 find p, so that R '(p) = 0

OpenStudy (danjs):

that will be the price that will maximize the revenue. the point on the curve (p , R(p))

OpenStudy (anonymous):

Oh, okay !^^ Thank you @DanJS

OpenStudy (danjs):

i am just curious where did you get 11233.33

OpenStudy (anonymous):

as the answer. since p=20/3

OpenStudy (danjs):

OpenStudy (danjs):

11233.33 is off the graph

OpenStudy (danjs):

(20/3 , 10667)

OpenStudy (anonymous):

20/3 goes in for p in the equation, I believe

OpenStudy (anonymous):

But i'm never sure. I just go with yours. ^^

OpenStudy (danjs):

R(20/3) = \[R(\frac{ 20 }{ 3 })=-15(\frac{ 20 }{ 3 })^2+200*\frac{ 20 }{ 3 }+10000\]

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