Question

Check my answer? Removable discontinuity?

Answer 1

I got D

Answer 2

i think its d

Answer 3

last one

Answer 4

A

Answer 5

when you factor the bottom, the x+5 factor cancels with the x=5 on the top, thus the root of this liner equation x+5 is a removable discontinuity.

There is a removable discontinuity at x=5

Answer 6

\(\dfrac{x+5}{x^2-25}=\dfrac{x+5}{(x+5)(x-5)}=\dfrac{1}{x-5} \)
on condition that \(x+5\ne 0\)
Therefore:
x+5=0 is a removable discontinuity, then removable discontinuity is at x=?

Answer 7

@mathmate x = -5?

Answer 8

Just checking, how did you get x=-5.