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Simplify the expression. (–3i)( –4i)
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@UnkleRhaukus
\[(-3i)(-4i)\\=(-1\times3\times i)\times(-1\times4\times i)\]we can rearrange \[=(-1\times-1)\times(3\times4)\times(i\times i)\\=\]
1 x 12 x i^2?
12i^2?
\[=1\times12\times i^2\\=12i^2\]good. Do you know what \(i^2 =?\)
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no?
\[\boxed{i = \sqrt{-1}}\qquad\implies\qquad i^2=\sqrt{-1}\times\sqrt{-1}=-1\]
so i^2=-1
yeah, which makes \[=12i^2\\=12(-1)\\=\]
-12
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Yes!
But if you haven't been studying complex numbers, maybe \(i\) is not supposed to be the imaginary unit, in which case you should just leave your answser as \(12i^2\)
ok.. i have 1 last question. someone gave me the answer but i wanted to how how to do it. could you help me one last time?
ok!
than you so so so much!
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