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help please Solve the following system of equations. x + y = 3 2x + 2y = 6
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We can solve it using substitution: x + y = 3 2x + 2y = 6 First re-arrange the 2nd equation: x + y = 3 Subtract y to both sides: x = -y + 3 Now we can plug in -y + 3 into the 2nd equation for 'x': 2x + 2y = 6 2(-y + 3) + 2y = 6 Distribute 2 into the parenthesis: -2y + 6 + 2y = 6 Can you add -2y + 2y? @brianna1000
would it be 0?
Yes, which gives us: 6 = 6 So the answer here will be 'Infinitely many solutions', meaning they're the same line.
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thank you an i did :)
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