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A=2I+B => B=A-2I = \(\left[\begin{matrix}2 & 2 & -1 \\ 0 & 2 & 2\\ 0 & 0 & 2\end{matrix}\right]\) -2\(\left[\begin{matrix}1 & 0 & 0 \\ 0 & 1 & 0\\ 0 & 0 & 1\end{matrix}\right]\) = ?
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Given A=\(\left[\begin{matrix}2 & 2 & -1 \\ 0 & 2 & 2\\ 0 & 0 & 2\end{matrix}\right]\) 1. Find B such that A=2I+B 2. Calculate\(B^2\) and \(B^3\) 3. Find \(A^n\) in terms of n. @mayliz (les autres tuteurs pourront vous donner de l'aide pour les parties 2 et 3) (avez-vous besoin de l'aide pour l'Ex 2?)
thanks a lot @mathmate ,now I can solve the rest of exercise
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