Question

i feel like im having a blonde moment so can someone help me out lol i will medal

Answer 1

lol who are you calling blonde?

Answer 2

\[x ^{3}+3x ^{2}y+4xy ^{2}+y ^{3}+xy ^{2}+x ^{2}y+3xy ^{2}\]

okay for some reason i forget when you put the like terms together like im getting mixed up with a couple of things

Answer 3

like terms would mean same variable with same exponents

Answer 4

for example \(x^3\) has no other like terms there

Answer 5

neither does \(y^3\)
but \(3x^2y\) and \(x^2y\) ARE like terms

Answer 6

This is what i was thinking for the answer, but the terms

\[x ^{3}+4x ^{2}y+3xy ^{2}+y ^{3}\]

Answer 7

okay the 3xysquared is supposed to b a four

Answer 8

no i don't think sow

Answer 9

so

Answer 10

x3 + 4x2y + 8xy2 + y3

Answer 11

not that either

Answer 12

srry x^3 + 4x^2y + 8xy^2 + y^3

Answer 13

\[x ^{3}+3x ^{2}y+4xy ^{2}+y ^{3}+xy ^{2}+x ^{2}y+3xy ^{2}\]
\[x^3+3x^2y+x^2y+4xy^2+xy^2+3xy^2+y^3\] has them grouped together

Answer 14

i know the like terms are

\[(3x ^{2}y, x2y) (xy ^{2},3xy2)\]

Answer 15

the 2 r both exponents i guess i didnt type it in properly

Answer 16

when you add them up it is
\[x^3+4x^2y+8xy^2+y^3\]

Answer 17

wait so where did the 8 come from

Answer 18

wait i think i know what happened i think i typed the problem in wrong wow im having a very off day lol

Answer 19

\[4xy^2+xy^2+3xy^2\\
4+1+3=8\]

Answer 20

ok i have an idea, start with the original question

Answer 21

because i bet we started in the middle right?

Answer 22

this is the question i think what happened was i made a dyslexic error lol

\[x ^{3}+3x ^{2}y+xy ^{2}+x ^{2}y+3xy ^{2}+y ^{3} \]

Answer 23

ok now it is real easy

Answer 24

\[x^3+4x^2y+4xy^2+y^3\]
was that the original problem?

Answer 25

okay so i was right lol thanks

Answer 26

hi