Question

The attachment below is what I need help with.

Answer 1

i do not know i am in 7th grade

Answer 2

have you ever heard of mathway

Answer 3

you might want to sign up so you can see the steps

Answer 4

Oh, I'm in 11th grade. And no never heard of Mathway.

Answer 5

yes you might want to go there

Answer 6

hey iam going to find a moderator

Answer 7

Ok, and I'm on mathway, but there's no help for Math Essentials. Thanks anyway.

Answer 8

wait i found a moderator

Answer 9

he/she will help you

Answer 10

Ok

Answer 11

he is on his way

Answer 12

here he is

Answer 13

Yeah I see him.

Answer 14

sorry, can't help you....lets see if others can help...have patience :)

Answer 15

i tried

Answer 16

That's the problem though, every time I ask for help I get ignored.

Answer 17

I'm dead.

Answer 18

whats the question

Answer 19

nvm

Answer 20

im in 09th but wat do you need help on

Answer 21

hold on

Answer 22

ill ask my brother real fast

Answer 23

I have to do a Factoring by Grouping thing for 4 questions. I posted a screenshot on here directions on how to do the essay and no it's not multiple choice.

Answer 24

my brother is a math genius ill go ask

Answer 25

I can't stay long, I have Art Club to go to in a few minutes. @MarsMcNugget

Answer 26

maby I can get some one to help can you post the 4 questions

Answer 27

It's in the screenshot I posted on here.

Answer 28

@MarsMcNugget is your brother able to help me or not?

Answer 29

I gtg, see you all in a hour or 2.

Answer 30

sorry he isnt home at moment i forgot

Answer 31

hey she has been needing help since this morning please dont ditch her here i will give you a medal

Answer 32

i didnt ditch her @zahviems

Answer 33

i couldnt help her

Answer 34

k im here

Answer 35

do u have an idea as to what to do first?

Answer 36

@AquaStone316

Answer 37

Sorry @ScarlettGrace<3 I had to go offline. I'm supposed to answer just the 4 questions in the attachment by this thing called Factoring by Grouping.

Answer 38

https://www.khanacademy.org/math/algebra/multiplying-factoring-expression/factoring-by-grouping/e/factoring_polynomials_by_grouping_1
probably this can help u

Answer 39

Thanks, but I need help for Math Essentials not Algebra.

Answer 40

I have to answer 4 questions in the essay for Math Essentials using Factoring by Grouping.

1. ac - bc + ad - bd
2. xy - 3x - 8y + 24
3. 4x^2y +20x +5y +xy
4. 48x^2y + 20xz + 12xy + 5z

Answer 41

ac - bc + ad - bd
\((ac - bc) + (ad - bd)\)
=\(c(a - b) + d(a - b)\)
Now, factor out the common factor, which is (a-b)
=\((c+d)(a-b)\)

Answer 42

That's for number 1

Answer 43

This is how you factor by grouping, does it make sense? :)

Answer 44

I think I got it, the (ac - bc) + (ad - bd) was my guess but wasn't sure if I had it right or not. But I still need help with the rest of them.

Answer 45

xy - 3x - 8y + 24
split the equation into two parenthesis, and factor some number. Make sure you factor the right number to get same numbers that can be factored out again. Like what i did with the previous, i chose to first factor c and d, and i came up with common variables (a-b) that can be factored out again.

Answer 46

@AquaStone316 , i worked the first problem through to make you understand what you're supposed to do, step by step. Are you able to work out the second problem while i'm here walking you through?

Answer 47

xy - 3x - 8y + 24
\(\bf Step~one\): split the equation

Answer 48

Ok uh, xy - 3x - 8y + 24 you split it like this (xy - 3x) - (8y + 24)?

Answer 49

\(\bf Step~2\) : Factor something common out from each parenthesis

Answer 50

I see that x and y are common from each parenthesis.

Answer 51

Everyone is helping you...stop asking in the group chat.

Answer 52

People keep leaving me so no not everyone is helping me.

Answer 53

Zale is helping.

Answer 54

refresh your page to eliminate the question marks things

Answer 55

So I got it right so far?

Answer 56

You didn't type anything of what you worked on, aqua

Answer 57

All you typed was "I see that x and y are common from each parenthesis."

Answer 58

You said factor something "common" out from each equation.

Answer 59

Go ahead and factor what you think is right.

Answer 60

Since x and y are common does that mean I factor them out or not?

Answer 61

x and y are not common..

Answer 62

X is common, but y is not common on the second parenthesis. (8y-24) there's only one y?

Answer 63

You could've just told me I had x right and y wrong.

Answer 64

But what about the last parenthesis, what should be factored out? y can't be factored out.

Answer 65

8? Because 8 x 3 = 24.

Answer 66

Yes!!!

Answer 67

:)

Answer 68

that means you should factor out 8 ^_^

Answer 69

Ok so x(y - 3) - 8(y + 24)?

Answer 70

x(y - 3) - 8(y - 3)
to check
- 8(y - 3) distribute -8 back again -8 *y and -8*-3, you would get -8y+24

Answer 71

now, factor out the common factor once again
x(y - 3) - 8(y - 3)

Answer 72

I don't get what I'm supposed to factor out. I see that y and 3 are common for both parenthesis if I factor both of them out I get nothing.

Answer 73

Yes, (y-3) is multiplied to both x and 8, factor that out and you're done :)

Answer 74

@AquaStone316 , i really can't go through every question you have on your homework. It seems that you need to practice more on group factoring.

Answer 75

Thanks anyway.

Answer 76

No problem, good luck with practicing! :)