Question

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Answer 1

2AlCl3(s) ---> 2Al(s) + 3Cl2(g)

Answer 2

start with the given amount, 78.3 mL Al, change to grams using density, change to moles using molar mass.....

Answer 3

that changes mL aluminum to moles aluminum

Answer 4

yeah,
then use the mole ratio from the balanced equation to switch to moles of aluminum chloride, then change to grams aluminum chloride with molar mass

Answer 5

i think it is 1044.83 g AlCl3

Answer 6

just set it up like above, and make sure the units cancel correctly , starting with what you are given, and ending with what you want to get

Answer 7

ill try, i just remember this stoichiometry stuff from chem freshman year a lonngg time ago, not sure about everything else. ill try though