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Chemistry 21 Online
OpenStudy (anonymous):

X

OpenStudy (danjs):

first calculate the volume of the iron block Volume = length x width x height [cm^3]

OpenStudy (danjs):

i am trying to remember, can you say 1 cm^3 of Fe = 1 mL Fe

OpenStudy (danjs):

i think so

OpenStudy (danjs):

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OpenStudy (danjs):

now you have grams of iron, use the molar mass to go over to moles of iron

OpenStudy (danjs):

then mole ratio to switch to moles of nitric acid

OpenStudy (danjs):

then molar mass of the acid to switch to grams acid

OpenStudy (danjs):

k

OpenStudy (danjs):

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OpenStudy (danjs):

what is the next fraction to multiply by

OpenStudy (danjs):

they want nitric acid HNO3 right now so far we have Mol Fe multiply by 6 mol HNO3 / 2 mol Fe from the equation to change to the HNO3

OpenStudy (danjs):

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OpenStudy (danjs):

now you have mol HNO3, they want grams, use the molar mass of nitric acid

OpenStudy (danjs):

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