N^2 = 6n+c , Solve for c to make perfect square
Cute
Why is there an \(=\) sign?
Should it be \(+\) or \(-\)?
Im not sure.. Whats cute about this..
Is it really an \(=\)?
Yes.
Then I think the first thing you have to do is move it all to one side.
Its a quadratic equation..
\[ n^2-6n-c=0 \]
In general, we would observe that \[ (n+a)^2 = n^2+an+an+a^2 = n^2+2an+a^2 \]
If we set them equal, then: \[ n^2+2an+a^2=n^2-6n-c \]And if we set the coefficients equal, we get: \[ 2a=-6\\ a^2=-c \]
When we solve the first equation\[ 2a=-6\implies a=-6/2=-3 \]We can put it into the second equation: \[ (-3)^2 = -c\implies 9=-c\implies c=-9 \]
So we would say: \[ \big (n-3\big)^2 = n^2-6n+9 \]And that \(c=-9\).
I think this question is difficult for no reason, but thank you.
Usually they have you memorize some formula
Like \(b/2\) or something
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