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Physics 17 Online
OpenStudy (anonymous):

A person holds a 12 kg crate 0.9 meters off the ground for 6 seconds. What is the work done done. Work is in jouls...please someone help, I've tried everything

OpenStudy (anonymous):

The formula used is work done= force x distance (or displacement). I'm not too familiar with this but from what I've learnt, to find the force, you have to use the formula F=mg. Therefore, \[F= 12kg \times 9.8 ms ^{-2}\] \[= 117.6 N\] Since, we already know that the displacement is 0.9m, we can just plug our values into the initial formula.\[W=Fd\] \[=117.6N \times 0.9m\] \[= 105.8 J\] I applied what I learnt. I really don't know where time fits in though. Keep researching, check google books and maybe you'll stumble across something helpful.

OpenStudy (shamim):

I think the body is static

OpenStudy (shamim):

m i right?

OpenStudy (shamim):

If so Then displacement d=0 Nd work w=0

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