If x2 + y2 = 21 and 2x - 2y = 2, then what is x? If there are two possible answers, then whats the larger of the 2
hi!!
\[x^2+y^2=21\\ 2x-2y=2\] or easier \[x-y=1\] so \[y=x-1\]
you can substitute \(x-1\) for \(y\) in the first line and solve \[x^2+(x-1)^2=22\] for \(x\)
you ok from that point on?
can you help me through it? @misty1212
ok we have to go ahead and square the second term \[x^2+(x-1)^2=x^2=(x-1)(x-1)\\ =x^2+x^2-2x+1\\ 2x^2-2x+1\]
okay I got that then what?
\[2x^2-2x+1=22\\ 2x^2-2x-21=0\] and if you are lucky it factors
I use the quadratic eqn right? @misty1212
hmm hold on usually these are cooked up to give nice answers, this one is ugly let me see if i made a mistake
ooh yesssss it was 21 not 22!
okay thank you! @misty1212
\[2x^2-2x+1=21\\ 2x^2-2x-20=0\]
still not that nice though \[x^2-x-10=0\]
then i do quadratic eqn? @misty1212
yes there is no avoiding it
what did you get for it? @misty1212
\[x=\frac{1\pm\sqrt{41}}{2}\] i think
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