Question

Is anyone good at Algebra 2?

Answer 1

Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = –1.

Answer 2

@whpalmer4 I'm pretty sure the answer is f(x) = 4x^2 right?

Answer 3

equidistant meaning
from the vertex to the focus, is the same distance as from the vertex to the directrix

what does that mean? well, the vertex is half-way between both of those

Answer 4

Ok so I'm right? My answer is correct?

Answer 5

half-way in between those 2 points... .if we keep on going up from the focus, notice that we're just moving between

(2,−1)→(2,−12)
↑half-way in between

Yes , you are correct! :)

Answer 6

Yes! Thank you! :) @samanthha

Answer 7

I'm not convinced hehe

Answer 8

im sorry about that, it didn't turn out like it was supposed to, but you are correct!

Answer 9

@xapproachesinfinity WHAT?!??!

Answer 10

@xapproachesinfinity So I'm wrong?!?

Answer 11

i said that was not a convincing answer to me! that's all!!
you can show all the work to why the answer must be that?

Answer 12

@xapproachesinfinity You must know the answer to that question? ;) Great! Now you've made me feel guilty :'(

Answer 13

eh why! i'm just not sure you answered right!
if you feel it is right then that's okay with me

Answer 14

@xapproachesinfinity So there is a possiblity that I'm wrong?!!!

Answer 15

hmm
i would do this first
\(\huge f(x)=a(x-h)^2+k\)
where (h,k) is the vertex
find the vertex by midpoint forumla

Answer 16

according to you if the equation is \(\huge f(x)=4x^2=4(x-0)^2+0\)
so the vertex is at (0,0)
is that true?

Answer 17

@xapproachesinfinity omg

Answer 18

hhehe actually you are correct!

Answer 19

but you didn't know how to justify it

Answer 20

I'm sorry, i should of actually explained.

Answer 21

@xapproachesinfinity I can honestly say I'm a great guesser lol

Answer 22

hehehe
no guesses okay

Answer 23

actually it is wrong

Answer 24

@jkasper are you kidding me???

Answer 25

it should be y=(1/4) x^2

Answer 26

@jkasper are you sure?