Solve the triangle. B = 73, b = 15, c = 8
@ganeshie8
I am coming up with 38.933 for a, but that isn't an option.
@nincompoop
how did you solve for it?
I would like to see your work
I did \(\sf \dfrac{15}{73}=\dfrac{8}{a}\), then cross multiplied coming up with \(\sf\dfrac{584}{15a}\) then divided by 15, \(\sf\dfrac{38.933}{a}\) then multiplied by a, ending up with a = 38.933
hmmm I don't think you are suppose to do that
the lower caps and caps denote side and angle respectively EXAMPLE |dw:1421391500285:dw|
so the B might be 73 degrees instead of measurement of a side length
have you learned laws of cosine and sine?
I used by as an angle.
That is what they are "teaching" us now.
hmmm
do you ave a copy of ck.org free trigonometry book?
I was thinking to use this: a/sin A = b/sin B = c/sin C
based on your solution, can you draw the triangle ?
|dw:1421391843633:dw|
oh okay, so you know about the law of sine and how about the law of cosine?
No, I haven't gotten to law of cosine yet
that is okay
|dw:1421392099270:dw|
|dw:1421392279631:dw| ^^ That's actually possible, you can approach it like that if you want
we can also use sinA/a = sinB/b = sinC/c
Actually I'd use Tan
Sorry had to switch over to my phone
you don't have enough to use pythagorean theorem @tHe_FiZiCx99 you can derive by utilizing laws of cosine, and maybe, just maybe you will get somewhere an easy path to solving this
let us first solve for the angle C, @sleepyjess and use the laws of sine
|dw:1421392663304:dw|
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