Find all the zeros. x^3+x^2=7x+7. Show all work.

Question

jhannybean · Answer

@WesternBurger ?

anonymous · Answer

Yeah?

jhannybean · Answer

Alright :) When finding zeroes, are you looking for real and complex,or just the real?

anonymous · Answer

Uhmm both? And hey I'm gonna close this question but I'm still gonna respond and everything. I just need to post a few more questions.

jhannybean · Answer

Hm,how about finishing this one,then opening up a new one?Just a suggestion...

anonymous · Answer

I know I usually do but I'm in a time crunch. It's almost 5:30 am I've been up since 4 and I need to start getting ready for school soon.

jhannybean · Answer

I see.This one won't take very long :)

jhannybean · Answer

Let's work on this. 

Move everything over to the left side. what is your equation?

anonymous · Answer

It would be... x^3+x^2-7x-7=0

jhannybean · Answer

Awesome,now group together two terms at a time. $$(x^3 +x^2) +(-7x-7)=0$$

jhannybean · Answer

Factor out your LCD.

anonymous · Answer

x^2(x+1) -7 (x+1) 

(x^2-7) (x+1)

So the zeros would be -1 and + or - square root of 7?

jhannybean · Answer

Actually,you got themboth right.

jhannybean · Answer

Good job.

anonymous · Answer

Would it be $$\pm \sqrt{7}$$ Maybe I just worded it wrong lol

jhannybean · Answer

I read it wrong at first.

anonymous · Answer

Oh ok, thanks so much! :)

jhannybean · Answer

No problem :)