Question

in need of Algebra 2 help asap..? Semesters over Tuesday and I'm behind :/ (Problem in the comments.)

Answer 1

So it's basic factoring for all of it to simplify:
\[\frac{ 5n ^{2}(m+3)(m-1) }{ 10n(m-2)(m-1) }\div \frac{ n ^{2}(m-6)(m+3) }{ 4n ^{2}(m-6)(m-2) }\]

All of those factors are there twice, and same factors in division can cancel out leaving:
\[\frac{ 5n ^{2}/10n }{ n ^{2}/4n ^{2} }\]

It can simplify even more, starting with the top:
5/10 is 1/2 and n^2/n is n. So you have n/2
The bottom just leaves 4.

So it looks like:
\[\frac{ 4n }{ 2 }\]

Which just equals 2n.

Sorry it takes a minute to type but I hope this helps!!

Answer 2

Thank you so much! (: @bruhhh

Answer 3

No problem! Hope it makes sense lol