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Engineering 21 Online
OpenStudy (anonymous):

done.

OpenStudy (jfraser):

you have a series of values, and need to create ratios out of them. Line up the units you have to make the ratios you're asked for.

OpenStudy (zzr0ck3r):

no idea

OpenStudy (anonymous):

@eyust707

OpenStudy (eyust707):

Dry unit weight = weight of solids/volume total

OpenStudy (eyust707):

Void ratio = Specific gravity* Unit weight of water/(dry unit weight) - 1

OpenStudy (eyust707):

Porosity = e/(1 + e)

OpenStudy (eyust707):

Saturation = moisture content* S.G./e

OpenStudy (eyust707):

I wouldn't memorize how to derive these just practice how to use and navigate through them given various parameters. I got these from my soils book.

OpenStudy (eyust707):

In your book there should be a section on relationships of soil properties.

OpenStudy (eyust707):

units are English units

OpenStudy (eyust707):

a is unitless b is lbs/ft^3 c is lbs/ft^3 d is unitless e is unitless f is unitless

OpenStudy (eyust707):

numbers look very high on some of those

OpenStudy (eyust707):

typically soil is 90-160 lbs per cubic foot

OpenStudy (eyust707):

moisture content is usually expressed as a percent

OpenStudy (anonymous):

okay i'll redue it and get back with you on it.

OpenStudy (anonymous):

@eyust707 a)15% b)120lbs/ft^3 c)104.4lbs/ft^3 d)5.29 e).84 f)94

OpenStudy (anonymous):

@eyust707

OpenStudy (eyust707):

oh i might have confused you a little with the S calculation. Usually (unless stated otherwise) when you plug in a percent like "15%" to an equation you should plug in ".15" not 15.

OpenStudy (eyust707):

One thing I do to help myself not only become a better student but to also become a better engineer is to constantly ask the question, "does this make sense?" or "is this answer practical?" The answer you put for f.) is a good example where this might have saved you. Degree of saturation is a ratio between the volume of the water in the soil sample to the volume of the voids (all the air pockets) in the soil sample. S = Vw/Vv Can there ever be more water than there are air pockets? Probably not. Therefore S can never be more than 1. If you do get an answer more than 1 you probably made a mistake. Using this logic more and more you'll be able to tell if your answer is possibly correct or not definitely incorrect without ever even doing the math.

OpenStudy (eyust707):

hehe i wasn't going to calc these out but I'll do it since you seem like a great student and very dedicated.

OpenStudy (anonymous):

uh i see. I'm guessing to that all my calculations might be off then?

OpenStudy (eyust707):

yes yes I made a typo in my formula I gave you

OpenStudy (eyust707):

I'm sorry

OpenStudy (eyust707):

e = G.s * Unit weight of water/dry unit weight - 1

OpenStudy (eyust707):

Here's the values I got a. .15 or 15% b. 120 lbs/ft3 c. 104.4 lbs/ft3 d. .572 e. 0.36 f. 0.69

OpenStudy (anonymous):

okay i will see where i went wrong. I might have even used the wrong numbers for the last three...

OpenStudy (eyust707):

Heres a few things to keep in mind: Moisture content is a percentage that indicates how mush weight of water is in the sample. Void ratio: A that tells you how much of the sample is air pockets compared to how much of the sample is solid. e = 1 would mean for every 1 air pocket theres the same volume in soil. e = .5 would mean there are half the amount of voids than there are dry solids. Porosity: very similar to void ratio. This is the volume of the voids in relation to the total volume of the sample. Porosity can never be more than 1. n =1 the sample is only air, n=0 the sample has no voids. Degree of saturation: How saturated is the sample? S = 1 would mean the sample is completely saturated. S=0 wouldn't mean the sample is completely dry.

OpenStudy (anonymous):

@eyust707 don't mean to bother you but when i get this right i will leave it at that. but i am still having trouble getting the last three d,e,f and i have redone them and still don't get the correct answer. d) 2.62*62.4/26.1-1= did not get the same thing e) e/ 1+e= did not get the same thing f)30*2.62/e= did not get the same thing. what on earth could i be pluging in wrong with my numbers?

OpenStudy (eyust707):

2.62* 62.4/104.4 - 1

OpenStudy (eyust707):

G.s * unit weight of water/dry unit weight - 1

OpenStudy (anonymous):

okay so for d) i get .572 and for e) i get .36. but f) i'm plugging in something wrong as well?

OpenStudy (anonymous):

for f) is it 0.25/.36=?

OpenStudy (eyust707):

Saturation = moisture content* S.G./e

OpenStudy (eyust707):

Saturation = .15 * 2.63/ .572 = .39/.572 = .68

OpenStudy (anonymous):

oh okay i will keep practicing this until it becomes natural to me. thanks for being patient with me and explaining the material the best way you could. I appreciate it. @eyust707

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