Question

Algebra 2 help.. @bruhhh

Answer 1

Okay the answer is (m-1) definitely.
You simplfy both the denominators first
\[\frac{ m-n }{ (m+n)(m-n) }+\frac{ m-1 }{ (m-n)(m-1) }\]
m-n and m-1 cancel leaving:
\[\frac{ 1 }{ m+n }+\frac{ 1 }{ m-n }\]
Which when you add them makes the bottom m^2-n^2
I'm honestly not sure how the 2m comes in at the top but none of the other equations are close to the answer so I hope this helps!

Answer 2

Thanks so much again! Really appreciate the help. I'm pretty behind with less than a week to catch up so it means a lot. @bruhhh

Answer 3

Oh jeez I know the feeling!! I procrastinate my work by coming on here lol good luck!

Answer 4

ugh, its tough. But thanks! you too (: