Find the domain of the following function:
f (x) = (3x+5) / (4x^2+9)
I know that the denominator cannot be equal to zero, but I'm getting stuck after that

Question

Find the domain of the following function:
f (x) = (3x+5) / (4x^2+9)
I know that the denominator cannot be equal to zero, but I'm getting stuck after that

anonymous · Answer

https://www.khanacademy.org/math/algebra2/functions_and_graphs/domain_range/v/domain-of-a-function

anonymous · Answer

Sorry determine what value for x would be in  the equation 4x^2+9 =0

anonymous · Answer

X would equal the sqr root of -9/4

anonymous · Answer

So the domain would be x is not equal to + or - sqr root (9/4)?

anonymous · Answer

X^2 = -9/4  or as you show x = square root of -9/4. Are either of these possible?

anonymous · Answer

You there?

anonymous · Answer

No, they will both give an answer of zero

anonymous · Answer

denominator is never 0 for any real value of x.

anonymous · Answer

There is no value that will result in a denominator of zero then, correct?

anonymous · Answer

so domain is all real values.

anonymous · Answer

Thus x can be all real numbers

anonymous · Answer

correct.

anonymous · Answer

Neither one of those are possible.

anonymous · Answer

Yes, @surjithayer . I know that the denominator cannot equal zero. I'm having trouble with finding the domain

anonymous · Answer

domain is the value of x which can satisfy the given  relation.
here x can have all real values
so domain is all real values .