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Mathematics 4 Online
OpenStudy (anonymous):

The tenth, eleventh, and twelfth terms of a sequence are shown in the table below: Term number 10 11 12 Term 21 24 27 Which of the following shows the first five terms of the sequence? a)9, 6, 3, 0, -3 b) -9, -6, -3, 0, 3 c) 6, 3, 0, -3, -5 d) -6, -3, 0, 3, 6

OpenStudy (anonymous):

do you need help?

OpenStudy (anonymous):

yessss

OpenStudy (freckles):

this is what kinda sequence?

OpenStudy (freckles):

do you notice a common difference among the terms?

OpenStudy (anonymous):

oh theres a diffrerence of 3

OpenStudy (freckles):

yes! 12->27 11->24 10->21 9->21-3 8->21-3(2) 7->21-3(3) 6->21-3(4) 5->21-3(5) 4->21-3(6) and so on hope you can see the pattern

OpenStudy (anonymous):

ohh i see it thank youu

OpenStudy (freckles):

what do you think the answer is?

OpenStudy (anonymous):

a ?

OpenStudy (freckles):

5th term is 21-3(5) = ? 4th term is 21-3(6) =? 3rd term is 21-3(7) =? 2nd term is 21-3(8)=? 1st term is 21-3(9)=?

OpenStudy (anonymous):

oh wait no its C

OpenStudy (freckles):

do those differences really carefully...

OpenStudy (freckles):

1st term gives you 21-3(9) which equals?

OpenStudy (anonymous):

-6

OpenStudy (freckles):

right does c have the first term being -6?

OpenStudy (freckles):

which choice has the first term as -6?

OpenStudy (anonymous):

no its d

OpenStudy (freckles):

right it is d

OpenStudy (anonymous):

oh lol kk thank you

OpenStudy (freckles):

here is another way if you have preferred \[\text{ Recall } a_n=a_1+d(n-1) \\ \text{ we are given } a_{10}=21 \\ a_{10}=a_1+d(10-1) \\ 21=a_1+3(10-1) \\ 21=a_1+3(9) \\ 21-3(9)=a_1 \] just like we found the long away for a_1 here

OpenStudy (anonymous):

wow thanks so much

OpenStudy (freckles):

np

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