The tenth, eleventh, and twelfth terms of a sequence are shown in the table below: Term number 10 11 12 Term 21 24 27 Which of the following shows the first five terms of the sequence? a)9, 6, 3, 0, -3 b) -9, -6, -3, 0, 3 c) 6, 3, 0, -3, -5 d) -6, -3, 0, 3, 6
do you need help?
yessss
this is what kinda sequence?
do you notice a common difference among the terms?
oh theres a diffrerence of 3
yes! 12->27 11->24 10->21 9->21-3 8->21-3(2) 7->21-3(3) 6->21-3(4) 5->21-3(5) 4->21-3(6) and so on hope you can see the pattern
ohh i see it thank youu
what do you think the answer is?
a ?
5th term is 21-3(5) = ? 4th term is 21-3(6) =? 3rd term is 21-3(7) =? 2nd term is 21-3(8)=? 1st term is 21-3(9)=?
oh wait no its C
do those differences really carefully...
1st term gives you 21-3(9) which equals?
-6
right does c have the first term being -6?
which choice has the first term as -6?
no its d
right it is d
oh lol kk thank you
here is another way if you have preferred \[\text{ Recall } a_n=a_1+d(n-1) \\ \text{ we are given } a_{10}=21 \\ a_{10}=a_1+d(10-1) \\ 21=a_1+3(10-1) \\ 21=a_1+3(9) \\ 21-3(9)=a_1 \] just like we found the long away for a_1 here
wow thanks so much
np
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