Question

Please need help with this problem been struggling on it

Answer 1

what seems to be the problem?

Answer 2

what is the question

Answer 3

i cant see the whole picture

Answer 4

what elements are in all three sets?

Answer 5

answers
1. 4/25 2. 2/25 3. 1/25 4. 3/25

Answer 6

@freckles 2

Answer 7

so AnBnC=2
but I don't know how to figure out P(2) without anything else given

Answer 8

@freckles me either

Answer 9

@freckles im confused

Answer 10

so there is nothing else given besides the picture you posted right?

Answer 11

I don't get 9
why is 9 inside A and also outside of A?
that is kinda weird

Answer 12

@mathslover or @Directrix opinions on this question?

Answer 13

@freckles nope nothing else just the answers i posted also

Answer 14

so the only numbers shown here are {2,4,5,6,7,8,9}
that is 7 numbers
I would think since 2 occurs once of these 7 numbers
P(2)=1/7

Answer 15

and like P(9)=2/7
and so on...

Answer 16

but 1/7 isn't an option

Answer 17

@freckles thats why im stuk just doesnt make sense unless im missing something

Answer 18

What is "9" outside there?

Answer 19

maybe there was a game that A,B, and C were playing
and there was a chance to win the element called 9 but no one won it
but there was also another chance to win 9 and A won it ?

Answer 20

if that makes sense
I guess I have the right translation of that now

Answer 21

wait a minute then that means there was 3 times to win 2

Answer 22

ok
2 times for 9
2 times for 5
1 time for 8
3 times for 2
2 times for 6
2 times for 4
1 time for 7

Answer 23

the number of times in all is
2+2+1+3+2+2+1

Answer 24

still can't get 25 on bottom

Answer 25

n(A) = 18
n(B) = 15
n(C) = 15

P(A) + P(B) + P(C) = 48

\(A \cup B \cup C = A + B + C - (A \cap B) - (A \cap C) - (B \cap C) + (A \cap B \cap C) \)

\(A \cap B \cap C = A \cup B \cup C - ( A + B + C - (A \cap B) - (A \cap C) - (B \cap C)) \)

\(A \cap B \cap C = 35 - (48 - 5 - 6 - 4) = 35-33 = 2\)

Hmm :/ My bad.

Answer 26

Aren't we required to find power set here?

Just use that, I guess.

Answer 27

@freckles ok i got it nowww i see where i was messing up noww

Answer 28

tell me please :p

Answer 29

@freckles hard to explain but got 1/25

Answer 30

err i don't get it lol
I would say the P(of getting a 2) is the number of times 2 occurs/the sum of amount of times the other numbers occur
which equal 3/(1+2+1+2+3+2+1+1)=3/(13)

Answer 31

i think i have to be misinterpreted in the information given

Answer 32

sum of the numbers=9+5+8+6+2+4+7+9
=14+14+6+16
=28+22
=50

P(2)=2/50=1/25

Answer 33

lol i guess that works

Answer 34

@freckles yes thats how i got it

Answer 35

@freckles and the answer was correct to

Answer 36

yea I totally was looking at the data a different way

Answer 37

http://www.stat.purdue.edu/~huang251/Slides2.pdf
here is another example on this power point thingy

Answer 38

it was done in a similar way that we were suppose to done here