lim x^6e^−x^5
x→∞

Question

lim   x^6e^−x^5
x→∞

anonymous · Answer

+∞

anonymous · Answer

How did you get that answer?

anonymous · Answer

and that answer is wrong…

anonymous · Answer

your question is unclear i read it wrong

anonymous · Answer

$$\lim_{x \rightarrow \infty} x^6e^-x^5$$

anonymous · Answer

Hope that helps

kainui · Answer

Here, if you want to make exponents that have more than one character in them you have to write them like this 
x^{stuff}

See, that's better.

$$\lim_{x \rightarrow \infty} x^6e^{-x^5}$$So @kaylah93 Have you ever used L'Hopital's rule before?

anonymous · Answer

also, that e is raised to the $$-x^5$$

and yes i have- i kinda got stuck in the verification process of l'hospital
.

kainui · Answer

Can you show me you steps?

anonymous · Answer

i solves it its 0

anonymous · Answer

So I just plugged in $$\infty  $$ 
$$(\infty)^6 e^(-\infty)^5$$

anonymous · Answer

solved*

anonymous · Answer

For l'Hospitals rule do can you still take the derivative of each if they are being multiplied instead of being divided?

kainui · Answer

Well to use L'Hopital's rule you need to have 0/0 or infinity/infinity. So to get it into that form, you have to rewrite the e part as $$\Large e^{-x^5} = \frac{1}{e^{x^5}}$$

anonymous · Answer

ah thank you, let me work it out really quick!

anonymous · Answer

so now @Kainui i have $$6\lim_{x \rightarrow \infty} x^5/e^(5x^4)$$