Question

Solve 5x2 = -30x - 65.

A.) x = -3 ± 2i
B.) x = -3 ± 4i
C.) x = -6 ± 2i
D. x = -6 ± 4i

Answer 1

5x^2 +30x + 65 = 0

A=5
B=30
C=65
\[x = \frac{ -B \pm \sqrt{B^2 - 4*A*C} }{ 2*A }\]

Answer 2

rewrite the equation and divide every term by 5

\[x^2 + 6x + 13 = 0\]

now use the general quadratic formula

Answer 3

I got x=-6 ± 4i not sure if im right

Answer 4

well its close just simplify

\[x = \frac{-6 \pm 4i}{2}\]

remove the common factor

Answer 5

So would it be D?

Answer 6

well there is a 2 in the denominator, and both terms in the numerator are positive

so halve the values in numerator

Answer 7

oh, its not D

Answer 8

so what would it be haha

Answer 9

Wait it would be A

Answer 10

correct

Answer 11

Solve -3x2 - 4x - 4 = 0.
Would this be C?


A.) x equals quantity of 2 plus or minus 4i square root of 2 all over 3
B.) x equals quantity of 2 plus or minus 2i square root of 2 all over 3
C.)x equals quantity of negative 2 plus or minus 2i square root of 2 all over 3
x eD.)quals quantity of negative 2 plus or minus 4i square root of 2 all over 3

Answer 12

well the general quadratic formula is

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

then multiply every term by -1 so you get, just makes things easy


a = 3 b = 4 and c = 4

so the roots are

\[x = \frac{-4 \pm \sqrt{16 - 48}}{6}\]

now simplify

Answer 13

ok im getting C still