Question

PLEASE HELP WILL GIVE MEDALS!!!!!
Solve, using the substitution method.

d + e = 2
d – e = 4

The solution is (3, –1).
The solution is (5, 1).
There is no solution.
There are an infinite number of solutions.

Answer 1

@zzr0ck3r

Answer 2

@zepdrix

Answer 3

@sammixboo

Answer 4

There is no solution??

Answer 5

Let's look at the second equation:\[\Large\rm d-e=4\]If we add \(\Large\rm e\) to each side we get,\[\Large\rm d=4+e\]I'm going to color it like this,\[\Large\rm \color{orangered}{d=4+e}\]And maybe it will help clarify what we're about to do.

Answer 6

Sorry had to fix my post >.<

Answer 7

We're going to use this and fix in some stuff in our first equation:\[\Large\rm \color{orangered}{d} + e = 2\]

Answer 8

From working with our first equation, we found that the letter d can be replaced by \(\Large\rm 4+e\).

Answer 9

That's the whole idea with substitution.
We want to replace one of the letters with some stuff involving the other letter.

Answer 10

So our equation:\[\Large\rm \color{orangered}{d} + e = 2\]becomes,\[\Large\rm \color{orangered}{4+e} + e = 2\]

Answer 11

Do you understand how to solve for the value of \(\Large\rm e\) from this point?

Answer 12

you know I appreciate you trying to help me learn this but honestly I really need this answer so could you please tell me which answer is correct?

Answer 13

No.

Answer 14

d + e = 2
de = 4

Solve for e for the first equation.

e = -d + 2

Substitute that for the second equation and solve for d:

d(-d + 2) = 4
-d² + 2d = 4
-d² + 2d - 4 = 0

By quadratic formula, which is d = (-b² ± √(b² - 4ac))/2a:

a = -1
b = 2
c = -4

Substituting those values to the formula gives:

d = (-2 ± √(2² - 4(-1)(-4)))/2(-1)
d = (-2 ± √(4 - 16))/-2
d = (-2 ± √-12)/-2

Since the discriminant b² - 4ac gives nonreal solutions, there are NO REAL SOLUTIONS for the system of equations.

Answer 15

So correct answer is no real solution!!! Sorry have no clue why there are question marks up there!:(

Answer 16

Thank you so much could you help me with more? it'd really help

Answer 17

sure...

Answer 18

The question didn't involve de=4.
I can't figure out where you got that from...

Answer 19

Solve the given system, using the substitution method.

y = 4x – 6
8x – 2y = 14

(14, 12)
(12, 14)
There are an infinite number of solutions.
There is no solution.

Answer 20

@Agl202

Answer 21

Ok so, The lines are parallel so they do not intersect. Meaning no solutions.

Answer 22

Thanks

Answer 23

Solve, using the substitution method.

2x + 3y = 1
y = x – 8

(0, –8)
(2, –6)
(4, –4)
(5, –3)

Answer 24

@zepdrix You just gonna do the math correctly, then u will understand were I got it from! Ok?

Answer 25

Can u put ur last question into a new one? Would realy help me... Thx: )

Answer 26

Loooool, but you didn't do the math correctly >.<
You chose the wrong answer...

Answer 27

@zepdrix Sorry I have proof!!!! Ok?