Question

Removable discontinuity help please?

Answer 1

Hi Miss Joe :)

Hmm so we have an `asymptotic discontinuity` if the denominator doesn't cancel out with anything.

If we ARE ABLE TO cancel the denominator out with something in the numerator, it is instead called a `removable discontinuity`.

Answer 2

We need to factor the numerator to properly see what's going on.
Do you remember your formula for the difference of cubes?

Maybe you learned something involving SOAP? Hehe

Answer 3

Do you understand how we can apply that to our numerator?\[\Large\rm x^3-1^3=?\]

Answer 4

@zepdrix I'm starting to see yeah, what do we replace for a and b in the right side of the equation?

Answer 5

Example:\[\Large\rm x^3-8\]This example expression is not currently written as the difference of cubes.
We need to write the second term as a cube.
Well, it turns out that 8 = 2 cubed.

Answer 6

So our expression is actually,\[\Large\rm x^3-2^3\]

Answer 7

Applying the formula would give us\[\Large\rm =(x-2)(x^2+2x+2^2)\]

Answer 8

Whatchu think lady joe joe? :o
still confused?

Answer 9

so x^3 - 2^3 = (x-2)(x^2 + 2x + 2^2) ?

Answer 10

@zepdrix