Does the following infinite geometric series diverge or converge? Explain.
7 + 21 + 63 + 189 + . .
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OpenStudy (anonymous):
An infinite geometric series converges if its common ratio r satisfies –1 < r < 1. Otherwise it diverges.
OpenStudy (anonymous):
It converges; it has a sum.
It converges; it does not have a sum.
It diverges; it has a sum.
It diverges; it does not have a sum.
OpenStudy (anonymous):
that means....r should be decimal
OpenStudy (anonymous):
it converges and has a sum
diverges and has no sum
OpenStudy (anonymous):
I can only pick one :o
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OpenStudy (mathmate):
Hint:
\(common~ratio\) means a given term divided by the previous term.
@PrincessKhiayla
OpenStudy (anonymous):
converges and have a sum
OpenStudy (anonymous):
Thank you @mathmate @lalithavasanth
OpenStudy (anonymous):
\[a _{n}\rightarrow \infty ~as~n \rightarrow \infty \]
hence it does not converge.
OpenStudy (anonymous):
I'm confused :o
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OpenStudy (anonymous):
\[a _{n}must \rightarrow 0~as~ n \rightarrow \]
OpenStudy (anonymous):
\[n \rightarrow \infty \]
OpenStudy (anonymous):
sorry i am leaving.
OpenStudy (anonymous):
So it does converge?
OpenStudy (mathmate):
@PrincessKhiayla
First, you recognize that this is a geometric series since each term divided by the previous is a constant. This ratio is called the common ratio.
Can you tell me the value of the common ratio r?
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OpenStudy (anonymous):
It doesn't say @mathmate
OpenStudy (mathmate):
No it doesn't.
You have to calculated it according to what I explained.