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Mathematics 8 Online
OpenStudy (moonlight93):

I gave up on this physics problem, help me please. I will upload the picture, it's a graph! -- what is the formula to use for such problem?

OpenStudy (moonlight93):

jimthompson5910 (jim_thompson5910):

are you familiar with calculus?

jimthompson5910 (jim_thompson5910):

if so, then you need to find the area under the velocity curve to get the total displacement

jimthompson5910 (jim_thompson5910):

usually that involves an integral, but luckily, you have straight lines. That means you can break this figure up into trapezoids, rectangles and triangles

jimthompson5910 (jim_thompson5910):

also, be careful about how they set up the y axis

OpenStudy (moonlight93):

no, not really, I took precal . can you give me formulas to use. thanks a lot for helping

jimthompson5910 (jim_thompson5910):

first I would draw in the x axis to help you see where it's at better (see attached) I drew the x axis in green

jimthompson5910 (jim_thompson5910):

the goal is to find the area of these three regions I colored in (see attached)

jimthompson5910 (jim_thompson5910):

take note that the two roots of that velocity function are at (15,0) and (70,0)

jimthompson5910 (jim_thompson5910):

the areas above the curve (the blue and pink region) represent positive displacement. They move the object in the positive direction the yellow area under the curve represents negative displacement. The object will move in the negative direction

OpenStudy (moonlight93):

finish please, I need to know this, I have many problems like this that I need to do

jimthompson5910 (jim_thompson5910):

do you know how to find the area of a triangle?

jimthompson5910 (jim_thompson5910):

that blue triangle has a base of 15, height of 20

OpenStudy (moonlight93):

1/2b*h

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

what is the area of the blue triangle

OpenStudy (moonlight93):

150

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

how about the area of that yellow trapezoid?

OpenStudy (moonlight93):

how did you know that base of blue triangle is 15, it's not clear

jimthompson5910 (jim_thompson5910):

do you see how the x-intercept is (15,0) ?

OpenStudy (moonlight93):

yes

OpenStudy (moonlight93):

it's not an exact number though right?

jimthompson5910 (jim_thompson5910):

so the base extends from (0,0) to (15,0) making it 15 units long

jimthompson5910 (jim_thompson5910):

it is

jimthompson5910 (jim_thompson5910):

it's the midpoint of 10 and 20 or of 0 and 30

jimthompson5910 (jim_thompson5910):

alternatively, you can find the equation of the line through (0,20) and (30,-20) then find the x-intercept of that equation

OpenStudy (moonlight93):

so the yellow triangle goes from 15-70

jimthompson5910 (jim_thompson5910):

or just find the midpoint of the segment through (0,20) and (30,-20) that midpoint is (15,0)

OpenStudy (moonlight93):

that's base= 55

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

yellow trapezoid, not triangle

jimthompson5910 (jim_thompson5910):

but you have the right idea in mind

OpenStudy (moonlight93):

oh, yeah. thnx so i'll figure the area of all shapes, than what?

jimthompson5910 (jim_thompson5910):

you add up the areas above the x axis then subtract off the areas below the x axis

jimthompson5910 (jim_thompson5910):

this will give the total displacement

OpenStudy (moonlight93):

what that be the final answer?

jimthompson5910 (jim_thompson5910):

if we label the three areas A1, A2, A3 (see attached), then we can get the total displacement D to be D = A1 - A2 + A3 notice how I'm subtracting off A2 since that area is below the x axis

jimthompson5910 (jim_thompson5910):

you then add that displacement to the starting position to get the ending position

jimthompson5910 (jim_thompson5910):

ending position = (starting position) + (total displacement)

OpenStudy (moonlight93):

A1= 150 A2= 750 A3= 50 150-750+50 = -550

jimthompson5910 (jim_thompson5910):

very good, you nailed that part

jimthompson5910 (jim_thompson5910):

the total displacement is -550, which means that this object moves 550 units in the negative direction

OpenStudy (moonlight93):

THANK YOU!! for helping :)

jimthompson5910 (jim_thompson5910):

so where is the final position?

OpenStudy (moonlight93):

isn't -550?

jimthompson5910 (jim_thompson5910):

it starts at _____ and moves 550 units in the negative direction ending up at _____

jimthompson5910 (jim_thompson5910):

that -550 is not the answer

jimthompson5910 (jim_thompson5910):

it just tells us how that position has changed not the final position

OpenStudy (moonlight93):

starts at -10

OpenStudy (moonlight93):

right

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

you add on (-550) to get the ending position

OpenStudy (moonlight93):

-560

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (moonlight93):

so it's starting position+ the total displacement = ending position

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (moonlight93):

cool, thank you :)

jimthompson5910 (jim_thompson5910):

np

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