I gave up on this physics problem, help me please.
I will upload the picture, it's a graph!
-- what is the formula to use for such problem?
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OpenStudy (moonlight93):
jimthompson5910 (jim_thompson5910):
are you familiar with calculus?
jimthompson5910 (jim_thompson5910):
if so, then you need to find the area under the velocity curve to get the total displacement
jimthompson5910 (jim_thompson5910):
usually that involves an integral, but luckily, you have straight lines. That means you can break this figure up into trapezoids, rectangles and triangles
jimthompson5910 (jim_thompson5910):
also, be careful about how they set up the y axis
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OpenStudy (moonlight93):
no, not really, I took precal . can you give me formulas to use. thanks a lot for helping
jimthompson5910 (jim_thompson5910):
first I would draw in the x axis to help you see where it's at better (see attached)
I drew the x axis in green
jimthompson5910 (jim_thompson5910):
the goal is to find the area of these three regions I colored in (see attached)
jimthompson5910 (jim_thompson5910):
take note that the two roots of that velocity function are at (15,0) and (70,0)
jimthompson5910 (jim_thompson5910):
the areas above the curve (the blue and pink region) represent positive displacement. They move the object in the positive direction
the yellow area under the curve represents negative displacement. The object will move in the negative direction
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OpenStudy (moonlight93):
finish please, I need to know this, I have many problems like this that I need to do
jimthompson5910 (jim_thompson5910):
do you know how to find the area of a triangle?
jimthompson5910 (jim_thompson5910):
that blue triangle has a base of 15, height of 20
OpenStudy (moonlight93):
1/2b*h
jimthompson5910 (jim_thompson5910):
yes
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jimthompson5910 (jim_thompson5910):
what is the area of the blue triangle
OpenStudy (moonlight93):
150
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
how about the area of that yellow trapezoid?
OpenStudy (moonlight93):
how did you know that base of blue triangle is 15, it's not clear
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jimthompson5910 (jim_thompson5910):
do you see how the x-intercept is (15,0) ?
OpenStudy (moonlight93):
yes
OpenStudy (moonlight93):
it's not an exact number though right?
jimthompson5910 (jim_thompson5910):
so the base extends from (0,0) to (15,0) making it 15 units long
jimthompson5910 (jim_thompson5910):
it is
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jimthompson5910 (jim_thompson5910):
it's the midpoint of 10 and 20
or of 0 and 30
jimthompson5910 (jim_thompson5910):
alternatively, you can find the equation of the line through (0,20) and (30,-20)
then find the x-intercept of that equation
OpenStudy (moonlight93):
so the yellow triangle goes from 15-70
jimthompson5910 (jim_thompson5910):
or just find the midpoint of the segment through (0,20) and (30,-20)
that midpoint is (15,0)
OpenStudy (moonlight93):
that's base= 55
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jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
yellow trapezoid, not triangle
jimthompson5910 (jim_thompson5910):
but you have the right idea in mind
OpenStudy (moonlight93):
oh, yeah. thnx so i'll figure the area of all shapes, than what?
jimthompson5910 (jim_thompson5910):
you add up the areas above the x axis
then subtract off the areas below the x axis
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jimthompson5910 (jim_thompson5910):
this will give the total displacement
OpenStudy (moonlight93):
what that be the final answer?
jimthompson5910 (jim_thompson5910):
if we label the three areas A1, A2, A3 (see attached), then we can get the total displacement D to be
D = A1 - A2 + A3
notice how I'm subtracting off A2 since that area is below the x axis
jimthompson5910 (jim_thompson5910):
you then add that displacement to the starting position to get the ending position
jimthompson5910 (jim_thompson5910):
ending position = (starting position) + (total displacement)
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OpenStudy (moonlight93):
A1= 150
A2= 750
A3= 50
150-750+50 = -550
jimthompson5910 (jim_thompson5910):
very good, you nailed that part
jimthompson5910 (jim_thompson5910):
the total displacement is -550, which means that this object moves 550 units in the negative direction
OpenStudy (moonlight93):
THANK YOU!! for helping :)
jimthompson5910 (jim_thompson5910):
so where is the final position?
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OpenStudy (moonlight93):
isn't -550?
jimthompson5910 (jim_thompson5910):
it starts at _____ and moves 550 units in the negative direction ending up at _____
jimthompson5910 (jim_thompson5910):
that -550 is not the answer
jimthompson5910 (jim_thompson5910):
it just tells us how that position has changed
not the final position
OpenStudy (moonlight93):
starts at -10
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OpenStudy (moonlight93):
right
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
you add on (-550) to get the ending position
OpenStudy (moonlight93):
-560
jimthompson5910 (jim_thompson5910):
yes
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OpenStudy (moonlight93):
so it's starting position+ the total displacement = ending position